A= 4 B= 2 C= -1
follow the formula ax^2 + bx + c= 0.
Answer:
Trapezoid 1 (left side):
Base 1 = 2
Base 2 = 5
Trapezoid 2 (right side):
Base 1 = 6
Base 2 = 8
Step-by-step explanation:
<u>1st trapezoid:</u>
b_1 = x
b_2 = x + 3
h = 4
Hence, area (from formula) would be:

<u>2nd trapezoid:</u>
b_1 = 3x
b_2 = 4x
h = 2
Putting into formula, we get:

Let's equate both equations for area and find x first:

We can plug in 2 into x and find length of each base of each trapezoid.
Trapezoid 1 (left side):
Base 1 = x = 2
Base 2 = x + 3 = 2 + 3 = 5
Trapezoid 2 (right side):
Base 1 = 3x = 3(2) = 6
Base 2 = 4x = 4(2) = 8
Given:


To find:
The obtuse angle between the given pair of straight lines.
Solution:
The slope intercept form of a line is
...(i)
where, m is slope and b is y-intercept.
The given equations are


On comparing these equations with (i), we get


Angle between two lines whose slopes are
is

Putting
and
, we get



Now,
and 
and 
and 
, so it is an obtuse angle and
, so it is an acute angle.
Therefore, the obtuse angle between the given pair of straight lines is 120°.
Answer:
I believe the answer is D.
Step-by-step explanation: