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Nine hundred thousands place
Answer:
3^x=9^{x+5}
Step-by-step explanation:
3^x=9^{x+5}
x^2-x-6=0
x^4-5x^2+4=0
\sqrt{x-1}-x=-7
\left|3x+1\right|=4
\log _2\left(x+1\right)=\log _3\left(27\right)
3^x=9^{x+5}
If request to solve;
\mathrm{Convert\:}9^{x+5}\mathrm{\:to\:base\:}3
9^{x+5}=\left(3^2\right)^{x+5}
\mathrm{Solve\:}\:x=2\left(x+5\right):\quad x=-10
In a parallelogram, the opposite angles will be congruent to each other.
In this parallelogram, angles B and C are congruent, and angles A and D are congruent.
We will work on angles B and C first. Set the two angles to equal each other:

Subtract 6 from both sides:

Subtract 6x from both sides:

Divide both sides by 6 to get x by itself:

x will equal 10.
Set angles A and D to equal each other:

Divide both sides by 3 to get y by itself:

y will equal 18.
The x and y values that make this quadrilateral a parallelogram will be x = 10, and y = 18.
Yes that is true the two triangles are congruent