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2 years ago

5

What is m 2DEC? In square ABCD, we know: AB = 6 and BE = 4.2

1 answer:

Alex787 [66]2 years ago

3 0

Answer:

As mentioned ABCD is a square

So <DEC is always 90 degree

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Help Help!!!!!!!!!!!!!!!

BabaBlast [244]

Answer:

$\frac{7}{10} y$

Step-by-step explanation:

To add fractions <em>with the same denominator</em>, simply add the numerators:

$\frac{a}{b} + \frac{c}{b} = \frac{a+c}{b}$

So:

$\frac{3}{10} y+\frac{4}{10} y=\frac{7}{10} y$

6 0

3 years ago

The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

Solving proportion 10\8=n\10

Zanzabum

$\frac { 10 }{ 8 } =\frac { n }{ 10 } \\ \\ 10\cdot \frac { 10 }{ 8 } =\frac { n }{ 10 } \cdot 10\\ \\ \frac { 100 }{ 8 } =n$

$\\ \\ n=\frac { 4\cdot 25 }{ 4\cdot 2 } \\ \\ \therefore \quad n=\frac { 25 }{ 2 }$

6 0

3 years ago

Read 2 more answers

What is the difference in volume, in cubic feet, of the two prism?

Olegator [25]

Answer:

What prisms

Step-by-step explanation:

7 0

3 years ago

In how many ways can the letters of the word ``COPYRIGHT'' be arranged?

PilotLPTM [1.2K]

Answer:

362,880 ways

Step-by-step explanation:

There are 9 letters so 9!

And none of them are repeated so 9!/0!

9! = 362,880

I hope this helps, and plz mark me brainliest!!

4 0

3 years ago