Basically when the object hits the ground, f(t) is equal zero. So all you need to do is to solve the quadratic equation:
-5t^2 + 20t + 60 = 0
D = b^2 - 4ac = 20^2 - 4 × (-5) × 60 = 400 + 1200 = 1600
t1 = (-b + sqrt(D)) / 2a = (-20 + 40) / (-10) = -2
t2 = (-b - sqrt(D)) / 2a = (-20 - 40) / (-10) = 6
Since time can't be negative, our solution is t2.
So the object will hit the ground in 6 seconds.
Answer:
x = log(1+√2) ≈ 0.38277569
Step-by-step explanation:
Let z = 10^x. Then the equation can be rewritten ...
z^2 -2z -1 = 0
z^2 -2z +1 -2 = 0 . . . . rewrite to a form with a square
(z -1)^2 = 2 . . . . . . . . . add 2
z -1 = ±√2 . . . . . . . . . . square root
z = 1 ± √2 . . . . . . . . . . add 1
From the definition of z, we know it must be positive, so the only viable solution here is ...
z = 10^x = 1+√2
x = log(1+√2)
x ≈ 0.38277569
Triangle is the measure of
Answer:
he son was 19
Step-by-step explanation:
if the son is the same age as his mom was when she gave birth to him you must divide the mothers ageby 2 so you get half her age which would be 28 then you subtract 9 and you get 19
56/2=28
28-9=19
