Answer:
let f(x)=2,
•In this function there is no x therefore it's a constant function represent as y=2 at x=0
• Therefore at f(0)=2 and even at x=2 it will be the same
• at f(2)=2 , coordinate will be (2,2)
•• at f(0)=2 , coordinate will be (0,2)
Step-by-step explanation:
The picture in the attached figure
we know that
total amount of sap =[3*(1/4)+2*(3/8)+4*(5/8)+1*(1)]
total amount of sap =[(3/4)+(6/8)+(20/8)+(1)]
total amount of sap =[(3/4)+(3/4)+(10/4)+(4/4)]
total amount of sap =[20/4]
total amount of sap =5 gallons
total of trees=10
<span>[amount of sap collected from each tree]=total amount of sap/total of trees
</span>
[amount of sap collected from each tree]=5/10----> 0.5 gallons per tree
the answer is0.5 gallons
Seven hundred seventy thousand and seventy
Answer:
<h3>1</h3>
Step-by-step explanation:
Given the expression:
![\lim_{n \to \infty} \frac{e^x+e^{-x}}{e^x-e^{-x}}\\](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7Be%5Ex%2Be%5E%7B-x%7D%7D%7Be%5Ex-e%5E%7B-x%7D%7D%5C%5C)
factor out e^x from the numerator and denominator
![\lim_{n \to \infty} \frac{e^x+e^{-x}}{e^x-e^{-x}}\\\lim_{n \to \infty} \frac{e^x(1+e^{-2x})}{e^x(1-e^{-2x})}\\\lim_{n \to \infty} \frac{(1+e^{-2x})}{(1-e^{-2x})}\\ = \frac{(1+e^{-2(\infty)})}{(1-e^{-2(infty)})}\\= \frac{1+0}{1-0}\\= 1\\](https://tex.z-dn.net/?f=%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7Be%5Ex%2Be%5E%7B-x%7D%7D%7Be%5Ex-e%5E%7B-x%7D%7D%5C%5C%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7Be%5Ex%281%2Be%5E%7B-2x%7D%29%7D%7Be%5Ex%281-e%5E%7B-2x%7D%29%7D%5C%5C%5Clim_%7Bn%20%5Cto%20%5Cinfty%7D%20%5Cfrac%7B%281%2Be%5E%7B-2x%7D%29%7D%7B%281-e%5E%7B-2x%7D%29%7D%5C%5C%20%3D%20%20%5Cfrac%7B%281%2Be%5E%7B-2%28%5Cinfty%29%7D%29%7D%7B%281-e%5E%7B-2%28infty%29%7D%29%7D%5C%5C%3D%20%5Cfrac%7B1%2B0%7D%7B1-0%7D%5C%5C%3D%201%5C%5C)
<em>Hence the limit of the given function is 1</em>
5+4/6
Result: 17/3
OR
5+1/2+1/6
5+4/6=17/3
Hope this helps!