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Delicious77 [7]
3 years ago
9

In parallelogram ARMY , angle A equals (3x+10)° and angle Y equals (2x+15.5)° what is X?

Mathematics
1 answer:
a_sh-v [17]3 years ago
8 0

Answer:

x = 5.5

Step-by-step explanation:

Since the shape is a parallelogram, the opposite angles are congruent. Angle A is opposite Angle Y so we can set their values equal to each other to solve for x:

3x + 10 = 2x + 15.5

Bring the variables to one side and the constants to the other:

<u>x = 5.5</u>

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Sam has $15 more dollars than Sarah, Casey has 2 times as much as Sam. The total they have all together is $95, how much money d
Alja [10]

Answers:

  • Sarah has  $12.50
  • Sam has  $27.50
  • Casey has  $55

======================================================

Explanation:

x = amount of money Sarah has

x+15 = amount of money Sam has, since he has $15 more than her

2(x+15) = amount of money Casey has, since he has twice as much as Sam.

Let's add up those three expressions and set that sum equal to 95

Solve for x.

Sarah + Sam + Casey = 95

x+(x+15) + 2(x+15) = 95

x + x + 15 + 2x + 30 = 95

4x+45 = 95

4x = 95-45

4x = 50

x = 50/4

x = 12.50

This says that Sarah has $12.50

That must mean Sam has x+15 = 12.50+15 = 27.50 dollars

And Casey must have 2*27.50 = 55 dollars.

----------------

As a check,

Sarah+Sam+Casey = 12.50+27.50+55 = 95

So the answer is confirmed.

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3 years ago
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Write the recurring decimal 0.5 as a fraction in its simplest form.​
sergejj [24]

Answer:

0.5×2/2=1/2 is the required fraction.

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Based on the following calculator output, determine the inter-quartile range of the dataset.
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Write the numbers In order from least to greatest,0.44, 3/8,0.5 2/5
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3/8 =0.375
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least to greatest would be
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I NEED HELP FAST what is y+1=5/6(x-2) in standard form?
Irina18 [472]

Answer:

\large\boxed{5x-6y=16}

Step-by-step explanation:

The standard form of an equation of a line:

Ax+By=C

We have the equation in the point-slope form. Convert:

y+1=\dfrac{5}{6}(x-2)\qquad\text{multiply both sides by 6}\\\\6y+6=6\!\!\!\!\diagup^1\cdot\dfrac{5}{6\!\!\!\!\diagup_1}(x-2)\\\\6y+6=5(x-2)\qquad\text{use the distributive property}\\\\6y+6=(5)(x)+(5)(-2)\\\\6y+6=5x-10\qquad\text{subtract 6 from both sides}\\\\6y+6-6=5x-10-6\\\\6y=5x-16\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\-5x+6y=5x-5x-16\\\\-5x+6y=-16\qquad\text{change the signs}\\\\\boxed{5x-6y=16}

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