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3 years ago

How do you solve 5(-3y-1)-(6-5y) if y=-6

Mathematics

1 answer:

Ksenya-84 [330]3 years ago

7 0

5(18-1)-(6+30)
85-36 = 49
Your answer if 49

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51 and 53 HELP PLS!!!!!!!

Gelneren [198K]

Hi!
Answers:

51. w=9/4

53. b=12

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2 years ago

Please help.. The math department is putting together an order for new calculators. The students are asked what model and color

Katena32 [7]

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The answer is D. Here is proof. PLEEEAAASE mark brainliest.

Step-by-step explanation:

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2 years ago

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What is the length of side AB of the triangle?

oee [108]

Start with the Pythagorean theorem{A²+B²=C², A and B are the sides and C is the Hypotenuse/Longest Side.}
2²+4²=C²
4+16=C²
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2 years ago

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2 years ago

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Which function has an inverse function?

daser333 [38]

Answer: Option B

Step-by-step explanation:

By definition, only those functions that are one to one have an inverse function.

A function is one by one if there are not two different input values, $x_1$ and $x_2$ , that have the same output value y

Note that the function $f(x)= \frac{|x+3|}{5}$ is not a one-to-one function

When x=2 $f(x)= \frac{|2+3|}{5}=1\ ,\ \ y=1$

When x=8 $f(x)= \frac{|-8+3|}{5}=1\ \ ,\ y=1$

Note that the function $f(x)= \frac{x^4}{7}+ 27$ is not a one-to-one function

When x=1 $f(x)= \frac{(1)^4}{7}+27\ ,\ \ y=\frac{190}{7}$

When x=-1 $f(x)= \frac{(-1)^4}{7}+27\ ,\ \ y=\frac{190}{7}$

Note that the function $f(x)= \frac{1}{x^2}$ is not a one-to-one function

When x=1 $f(x)= \frac{1}{(1)^2}\ ,\ \ y=1$

When x=-1 $f(x)= \frac{1}{(-1)^2}\ ,\ \ y=1$

Then the answer is the option B.

You can verify that The function $f (x) = x ^ 5-3$ is a one-to-one function and therefore its inverse is a function

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2 years ago