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3 years ago

9

What’s the area of rhombus ABCD if ac =10 and BD=13 ?

1 answer:

kompoz [17]3 years ago

7 0

Rhombus Area = (Long Diagonal * Short Diagonal) / 2

Rhombus Area = ( 13 * 10 ) / 2

Rhombus Area = 65

Answer is B

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Bad White [126]

Part A

The given expression is:

$(-5(1+2i)+3i(3-4i)$

We expand to get:

$-5-10i+9i-12i^2$

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Part Bi)

The given expression is;

$\sqrt{-50}$

We simplify to get:

$\sqrt{25\times 2\times -1}$

$\sqrt{25\times} \sqr{2}\times \sqrt{-1}$

Note that:

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Part bii)

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We simplify to get

$\sqrt{\frac{-50 }{5}}$

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$\sqrt{-25}=\sqrt{25}\times \sqrt{-1}$

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Part C

We want to simplify:

$i^{22}$

We rewrite in terms of $i^2$

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$i^{22}=(-1)^{11}$

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