Answer:
Pamela = 30
Jiri = 40
Step-by-step explanation:
Two equations needed:
J-10 = P
P+J = 70
Plug and solve:
(J-10) + J = 70
2J - 10 =70
2J = 80
J = 40
40 - 10 = P
P=30
The correct question is
Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4−x and y = 8-x^-1 intersect are the solutions of the equation 4−x = 8-x^-1<span>.
Part B: Make tables to find the solution to 4−x = </span>8-x^-1<span>. Take the integer values of x between −3 and 3.
Part C: How can you solve the equation 4−x = </span>8-x^-1 graphically?
Part A. We have two equations: y = 4-x and y = 8-x^-1
Given two simultaneous equations that are both to be true, then the solution is the points where the lines cross. The intersection is where the two equations are equal. Therefore the solution that works for both equations is when
4-x = 8-x^-1
This is where the two graphs will cross and that is the common point that satisfies both equations.
Part B
see the attached table
the table shows that one of the solutions is in the interval [-1,1]
Part C To solve graphically the equation 4-x = 8-x^-1
We would graph both equations: y = 4-x and y = 8-x^-1
The point on the graph where the lines cross is the solution to the system of equations.
using a graph tool
see the attached figure N 2
the solutions are the points
(-4.24,8.24)
(0.24,3.76)
The taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16
/2!+...........
Given a function f(x)=9/x,a=-4.
We are required to find the taylor series for the function f(x)=8/x centered at the given value of a and a=-4.
The taylor series of a function f(x)=
Where the terms in f prime
(a) represent the derivatives of x valued at a.
For the given function.f(x)=8/x and a=-4.
So,f(a)=f(-4)=8/(-4)=-2.
(a)=
(-4)=-8/(![-4)^{2}](https://tex.z-dn.net/?f=-4%29%5E%7B2%7D)
=-8/16
=-1/2
The series of f(x) is as under:
f(x)=f(-4)+![f^{1}(-4)(x+4)/1!+ f^{11}(-4)(x+4)^{2}/2!.............](https://tex.z-dn.net/?f=f%5E%7B1%7D%28-4%29%28x%2B4%29%2F1%21%2B%20%20f%5E%7B11%7D%28-4%29%28x%2B4%29%5E%7B2%7D%2F2%21.............)
![=8/(-4)-8/(-4)^{2} (-4)(x+4)/1!+ 24/(-4)^{3} (-4)(x+4)^{2}/2!.............](https://tex.z-dn.net/?f=%3D8%2F%28-4%29-8%2F%28-4%29%5E%7B2%7D%20%28-4%29%28x%2B4%29%2F1%21%2B%20%2024%2F%28-4%29%5E%7B3%7D%20%28-4%29%28x%2B4%29%5E%7B2%7D%2F2%21.............)
=-2+2(x+4)/1!-24/16
/2!+...........
Hence the taylor series for the f(x)=8/x centered at the given value of a=-4 is -2+2(x+4)/1!-24/16
/2!+...........
Learn more about taylor series at brainly.com/question/23334489
#SPJ4
Answer:
y = 2x - 3
Step-by-step explanation:
We are given the slope, m = 2
Our standard formula of a line is y = mx + b, so we can substitute for the x and y values of the point (3, 3). If you did not know, the x-value and the y-value are both 3 because the point (3, 3) = (x, y).
So, our equation looks like this:
3 = (2)(3) + b
We can solve for b:
3 = 6 + b
b = -3
And now we have our equation of a line:
y = 2x - 3