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kipiarov [429]
3 years ago
5

Simplify the expression

Mathematics
1 answer:
erastova [34]3 years ago
6 0

Answer : A

We need to simplify the given expression

Lets factor numerator first

2x^2-5x-3 =(2x+1)(x-3)

x^2+8x+15 =(x+5)(x+3)

Now we factor the denominator

x^2+x-20 =(x+5)(x-4)

2x^2+9x+4 =(2x+1)(x-4)

Now we simplify it

\frac{(2x+1)(x-3)}{(x+5)(x-4)} * \frac{(x+5)(x+3)}{(2x+1)(x-4)}

Now cancel out same factors. so we left with

\frac{(x+3)(x-3)}{(x+4)(x-4)} }

Now multiply the factors

\frac{x^2-9}{x^2-16} }



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Step-by-step explanation:

You can think of point (-3, -6) as the center of a circle of radius 7. Then all points on the circle are 7 units from point (-3, -6). There are 4 points 7 units away from point (-6, -3) whose coordinates are easy to find. Think of a vertical line and a horizontal line that go through point (-3, -6). Up and sown from point (-3, -6) are points (-3, 1) and (-3, -13). To the right and left of point (-3, -6) are points (4, -6) and (-10, -6).

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Es urgente ¡¡¡ si la MH de a y 4 es 6 y la MH de 8 y b es 12 calcula la MH de a y b
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Sabemos que:

MH(x, y) = \frac{2xy}{x+y}

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Con esto podemos encontrar el valor de a:

8*a/(a+ 4) = 6

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