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kipiarov [429]
3 years ago
5

Simplify the expression

Mathematics
1 answer:
erastova [34]3 years ago
6 0

Answer : A

We need to simplify the given expression

Lets factor numerator first

2x^2-5x-3 =(2x+1)(x-3)

x^2+8x+15 =(x+5)(x+3)

Now we factor the denominator

x^2+x-20 =(x+5)(x-4)

2x^2+9x+4 =(2x+1)(x-4)

Now we simplify it

\frac{(2x+1)(x-3)}{(x+5)(x-4)} * \frac{(x+5)(x+3)}{(2x+1)(x-4)}

Now cancel out same factors. so we left with

\frac{(x+3)(x-3)}{(x+4)(x-4)} }

Now multiply the factors

\frac{x^2-9}{x^2-16} }



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The three additional points seem arbitrary, so let's choose x=0,1,2. We have:


f(0)=\frac{1}{2}sqrt(0+1) = \frac{1}{2}


So, the second point is (0,\frac{1}{2})


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So, the third point is (1,\frac{\sqrt{2}}{2})


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Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units. Which statements bes
valentinak56 [21]

Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.

By the definition of rhombus, diagonals meet at right angles.

Implies that PQ = QA

x+2 = 3x - 14

x-3x=-14-2

-2x=-16

2x = 16

dividing by 2 on both sides, we will get,

x =\frac{16}{2}

<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>

The line segment \overrightarrow{PA}=\overrightarrow{PQ}+\overrightarrow{QA}

\overrightarrow{PA}=x+2+3x-14

=4x-12

=4(8)-12 ( since x=8)

=32-12

=20

<h3>∴ \overrightarrow{PA}=20 units</h3>
3 0
3 years ago
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