All categories

3 years ago

\(\left\{-16,1 4,1 - 1,... \right\}V Formulate

Mathematics

1 answer:

lakkis [162]3 years ago

7 0

Answer:

−

(

−

)

{

⋯

}

Step-by-step explanation:

We have the sequence

{

−

⋯

}

By looking at the first three terms of the sequence, we can already see a pattern.

Starting at -16, each term has its sign reversed, and is divided by 4.

Hence the sequence can be written as:

{

−

(

−

)

−

(

−

)

⋯

}

So the formula for the

th term of the sequence is

−

(

−

)

{

⋯

}

You might be interested in

Need help asap —————-

mario62 [17]

Answer:

I believe it's 15,000//B

3 0

3 years ago

What is the missing value in x2y8 · x3y? = x5y5?

sweet-ann [11.9K]

Answer:

-3

Step-by-step explanation:

To find:

The value of '?' in the following expression:

$x^2y^8.x^3y^? = x^5y^5$

Solution:

First of all, let us have a look at a few rules of the exponents:

$1.\ a^b.a^c=a^{b+c}$

$2.\ a^b.a^{-c}=a^{b-c}$

Let us apply these rules and try to find out the missing value ('?') in the given expression.

Left Hand Side (LHS):

$x^2y^8.x^3y^?\\\Rightarrow x^2.x^3.y^8.y^?\\\Rightarrow x^{2+3}y^{8+?}\\\Rightarrow x^{5}y^{8+?}$

Now, let us compare the LHS with RHS, we get:

$x^{5}y^{8+?} = x^{5}y^{5}$

Dividing with $x^5$ on both sides:

$y^{8+?} = y^5\\\Rightarrow 8+? = 5\\\Rightarrow ? = 5-8 \\\Rightarrow ? =-3$

Therefore, the missing value in the expression is -3.

4 0

3 years ago

Find the surface area of this cylinder.

borishaifa [10]

Formula for the surface area of a cylinder: 2 x pi x r^2 + 2 x pi x r x h

Radius (r) = 3

Height (h) = 3

2 x pi x 3^2 + 2 x pi x 3 x 3

2 x pi x 9 + 2 x pi x 9

18pi + 18pi

36pi = 113.1 cm^2

Hope this helps!

4 0

3 years ago

Read 2 more answers

A line can intersect a circle in

juin [17]

Answer:

A line that intersects a circle in exactly one point is called a tangent and the point where the intersection occurs is called the point of tangency.

Step-by-step explanation:

5 0

3 years ago

Help me to answer this pls

Butoxors [25]

Problem 1

Draw a straight line and plot X anywhere on it.

Use your compass to trace out a circle with radius 1.5 cm. The circle intersects the line at two points. Let's make Y one of those points.

Also from point X, draw a circle of radius 2.5

This second circle will intersect another circle of radius 3.5 and this third circle is centered at point Z.

Check out the diagram below to see what I mean.

=====================================================

Problem 2

Draw a straight line and plot L anywhere on it.

Adjust your compass to 4 cm in width. Draw a circle around point L.

This circle crosses the line at two spots. Focus on one of those spots and call it M.

Draw another circle centered at point M. Keep the radius at 4 cm.

The two circles intersect at two points. Focus on one of the points and call it N.

The last step is to connect L, M and N to form the equilateral triangle.

See the image below.

=====================================================

Problem 3

I'm not sure how to do this using a compass and straightedge. I used GeoGebra to make the figure below instead. It's a free graphing and geometry program which is very useful. I used the same app to make the drawings for problem 1 and problem 2 earlier.

6 0

3 years ago