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3 years ago

4000-1375 and I need work

1 answer:

8 0

4000
-1375
———

Take 1 from the number 4 and have it go down the line of zeros.

39910
-1375
———-

Subtract

39910
-1375
———-
2,625

I hope this helped!

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Pls help I will give you 15 points only

QveST [7]

N= 1/8 I’m pretty sure I did that last year

6 0

3 years ago

ian is in training for a national hot dog eating contest on the 4th of july. on his first day of training, he eats 4 hot dogs. e

spin [16.1K]

Answer: $a_n = 4(1.1)^{n-1}$

Step-by-step explanation:

Since, the initial number of hot dogs = 4

According to the question,

The number of hot dogs is increasing by 110% of that of previous day,

Thus, the number of hot dog in first day = 4

Second day = 110 % of 4 = 4.4

Third day = 110% of 4.4 = 4.84

Fourth day = 110% of 4.84 = 5.324

So on.......

Thus, we get a GP,

4, 4.4, 4.84, 5.324 ..........................

That having common ratio, d = 1.1

And, first term, a = 4

Since, the nth term of the GP, $a_n = a\times d^{n-1}$

Hence, the required explicit formula of the given situation,

$a_n = 4(1.1)^{n-1}$

7 0

4 years ago

Read 2 more answers

10. On the playground, Grace threw the ball 3 more feet than Ella. Grace threw the ball 21

Vlad1618 [11]

Answer:

18ft

Step-by-step explanation:

21-3=18

5 0

3 years ago

Pls help me and hve a nice day ;p

Art [367]

Step-by-step explanation:

km²

make it braintliest please

3 0

3 years ago

Given quadrilateral EFGH at e(-4,7) f(8,4) G(t,-5) and h(-7,-1) using coordinate geometry prove EFGH is a rectangle

Tcecarenko [31]

The above question was not properly written.

Complete Question

Given quadrilateral EFGH with vertices at E(-4,8), F(8,4), G(5,-5) and H(-7,-1), prove using coordinate geometry that EFGH is a rectangle.

Answer:

Quadrilateral EFGH is a rectangle.l because:

EF = GH and FG = EH

Step-by-step explanation:

The formula for coordinate geometry is given as :

√(x2 - x1)² + (y2 - y1)² when we have coordinates: (x1, y1) and (x2 , y2)

For the quadrilateral EFGH with given coordinates above to be a rectangle,

EF = GH

FG = EH

Hence:

For side EF

E(-4,8), F(8,4)

= √(8 - (-4))² + (4 - 8)²

= √12² + -4²

= √144 + 16

= √160 units

For side FG

F(8,4), G(5,-5)

=√(5 - 8)² + (-5 - 4)²

= √-3² + -9²

= √9 + 81

= √90 units

For Side GH

G(5,-5) , H(-7,-1)

= √(-7 - 5)² + (-1 - (-5))²

= √-12² + 4²

= √144 + 16

= √160 units

For side EH

E(-4,8), H(-7,-1)

= √(-7 -(-4))² +(-1 - 8)²

= √-3² + -9²

= √9 + 81

= √90 units

From the above calculation, we can see that truly,

EF = GH

FG = EH

Therefore, quadrilateral EFGH is a rectangle.

6 0

3 years ago