Here's the solution :
- Side of the equilateral triangle = x
perimeter of equilateral triangle = 3 × x = 3x
perimeter of square = 4 × (x + 10)
now, according to above statement :
permission (square) = 3 × perimeter (triangle)
that is :
therefore, side of triangle = 8 cm
- perimeter (triangle) = 8 × 3 = 24 cm
- side of square = 8 + 10 = 18 cm
- perimeter of square= 18 × 4 = 72 xm
The equation is y=16(1.35)ˣ.
This equation is of the form y=a(1+r)ˣ, where a is the initial amount, r is the rate of growth expressed as a decimal number, y is the total, and x is the amount of time. For our problem, a is 16; b is 0.35 (35%=35/100=0.35). This gives us the equation above.
Answer:
x = -2/5
y = 12/5
Step-by-step explanation:
Substitution method;
-2x + 3y = 8 -----------(i)
x + y =2 -----------(ii)
x = 2 - y
substitute the value of x in equ (i)
(-2)* (2-y) + 3y = 8
-4 + 2y + 3y = 8
5y = 8 + 4
y = 12/5
substitute the value of y in equ (ii)
x + 12/5 = 2
x = 2 - 12/5
= 2*5/1*5 - 12/5
= 10 -12/5 = -2/5
Ans: x = -2/5
y = 12/5
elimination method:
-2x + 3y = 8 -----------(i)
x + y =2 -----------(ii)
(i) ====> -2x + 3y = 8
multiply equ (ii) by 2 ====> <u> 2x + 2y = 4</u>
add (i) and (ii) 5y = 12
y = 12/5
Substitute in equ (ii)
x + 12/5 = 2
x = 2 - 12/5
= 2*5/1*5 - 12/5
= 10 -12/5 = -2/5
Ans: x = -2/5
y = 12/5
Answer: 720 ways
Step-by-step explanation:
Given
A train has 1 main engine and remaining 6 train cars
If the engine is always in the front the remaining train cars can be arranged is
Answer:
c.k¹¹
Step-by-step explanation:
Anything raised to the power of 0 is one so k^0=1
k^4k^7
Since they have the same base you can just add them
4+7=11
