The estimated cost of first time DUI roughly around $1,000 dollars once the potential cost are factored in. The potential cost of a contract is the sum of all the estimated and actual cost of all the fees and reimbursable expenses associated with contact.
Answer:
c. $4,025,200
Explanation:
The computation of the total cash receipts from sales and collections in April month is shown below:
= April sales × cash sales percentage + April sales × credit sales percentage × collection month percentage + March sales credit sales percentage × Following month collection percentage
= $4,000,000 ×30% + $4,000,000 × 70% × 40% + $4,200,000 × 70% × 58%
= $1,200,000 + $1,120,000 + $1,705,200
= $4,025,200
Since cash sales are 30% , so the credit sales would be 70%
Answer:
Preparation of a statement of cash flows involves five steps
1. Compute net cash provided or used by operating activities.
This is the section where all the cash flow that belongs to the operating section are been added and subtracted according to the inflow and outflow of the transaction.
2. Compute net cash provided or used by investing activities.
This is the section where all the cash flow that belongs to the investing section are been added and subtracted according to the inflow and outflow of the transaction.
3. Compute net cash provided or used by financing activities.
This is the section where all the cash flow that belongs to the financing section are been added and subtracted according to the inflow and outflow of the transaction.
4. Compute the net increase or decrease in cash
This is the section where the cash-flow from operating, investing and financing activities is been balanced.
5. Report the beginning and ending cash balances and prove that the ending cash balance is explained by net cash flows.
After the cash-flow from operating, investing and financing activities is been calculated, Then, this section is also computed to derive the Closing/Ending cash balance
Answer:please refer to the explanation section
Explanation:
Mechanic = $100
Vet = $100
Alex (payment from vet) = $100
Will's $100 bill has created $300.
This situation is explained in detail by the concept known has the multiplier. The multiplier measures how much impact will a change in an exogenous variable will cause in endogenous variables, for example How much a increase in Government spending will change Gross Domestic Product.
The multiplier in this case is 3,
Answer:
A) Single-server single-phase model (M/M/1).
![\lambda=2.5 \,customers/hour\\\\\mu=6\,customers/hour](https://tex.z-dn.net/?f=%5Clambda%3D2.5%20%5C%2Ccustomers%2Fhour%5C%5C%5C%5C%5Cmu%3D6%5C%2Ccustomers%2Fhour)
B) The goal is not met, as the average time waiting for service is 5.56 minutes.
C) The new mean service rate is 7.5 customers/hour.
In this case, the average time waiting for service is 4 minutes, so the goal is met.
Explanation:
A) This situation can be modeled as a single-server single-phase model (M/M/1).
The mean arrival rate is 2.5 customers per hour.
![\lambda=2.5 \,customer/h](https://tex.z-dn.net/?f=%5Clambda%3D2.5%20%5C%2Ccustomer%2Fh)
The mean service rate is 6 customers per hour, calculated as:
![\mu=\frac{60\, min/h}{10 \,min/customer}=6\, customer/h](https://tex.z-dn.net/?f=%5Cmu%3D%5Cfrac%7B60%5C%2C%20min%2Fh%7D%7B10%20%5C%2Cmin%2Fcustomer%7D%3D6%5C%2C%20customer%2Fh)
B) The average waiting time for a customer can be expressed as:
![W_q=\frac{\lambda}{\mu}\frac{1}{\mu-\lambda} =\frac{2.5}{6}\frac{1}{6-2.5} =0.417*0.222=0.093\,hours\\\\W_q=0.093\,hours*(60min/h)=5.56 \,min](https://tex.z-dn.net/?f=W_q%3D%5Cfrac%7B%5Clambda%7D%7B%5Cmu%7D%5Cfrac%7B1%7D%7B%5Cmu-%5Clambda%7D%20%20%3D%5Cfrac%7B2.5%7D%7B6%7D%5Cfrac%7B1%7D%7B6-2.5%7D%20%3D0.417%2A0.222%3D0.093%5C%2Chours%5C%5C%5C%5CW_q%3D0.093%5C%2Chours%2A%2860min%2Fh%29%3D5.56%20%5C%2Cmin)
The average waiting time is 5.56 minutes, so it is more than the goal of 5 minutes.
C) If the average time spent per customer to 8 minutes, the mean service rate becomes
![\mu=\frac{60\, min/h}{8 \,min/customer}=7.5\, customer/h](https://tex.z-dn.net/?f=%5Cmu%3D%5Cfrac%7B60%5C%2C%20min%2Fh%7D%7B8%20%5C%2Cmin%2Fcustomer%7D%3D7.5%5C%2C%20customer%2Fh)
An the average waiting time for the service now becomes:
![W_q=\frac{\lambda}{\mu}\frac{1}{\mu-\lambda} =\frac{2.5}{7.5}\frac{1}{7.5-2.5} =0.333*0.2=0.067\,hours\\\\W_q=0.067\,hours*(60min/h)=4 \,min](https://tex.z-dn.net/?f=W_q%3D%5Cfrac%7B%5Clambda%7D%7B%5Cmu%7D%5Cfrac%7B1%7D%7B%5Cmu-%5Clambda%7D%20%20%3D%5Cfrac%7B2.5%7D%7B7.5%7D%5Cfrac%7B1%7D%7B7.5-2.5%7D%20%3D0.333%2A0.2%3D0.067%5C%2Chours%5C%5C%5C%5CW_q%3D0.067%5C%2Chours%2A%2860min%2Fh%29%3D4%20%5C%2Cmin)
The average time is now 4 minutes, so the goal is achieved.