All categories

3 years ago

Simplify the expression 4x+10+6x+2x

Mathematics

2 answers:

il63 [147K]3 years ago

5 0

Answer:

12X+10

Step-by-step explanation:

It's easy. Just combine like terms. Like terms must have the same variable and to the same power in this case all the terms have a power of 1, but it doesnt show it because it doesn't really matter. So 4x,6x, and 2x all have the same variable so add them together. That gets you 10x. Since nothing else in the expression has the same variable with 10, you leave the 10 at the end resolving in 12x+10

Liula [17]3 years ago

4 0

Answer:

12x+10

Step-by-step explanation:

Collect the like terms to one side.

You might be interested in

What percentage is 15 out of 40

irina1246 [14]

Answer:

the answer is 6

Step-by-step explanation:

so you do 15 multiply by 40 and divide by 100

5 0

3 years ago

Read 2 more answers

Six more than five times a number (x) is at least twenty-one

I am Lyosha [343]

The answer to this would be 5x+6>=21. Just wanted points :P

3 0

3 years ago

ILL MARK U AS BRAINLIEST PLS HELP

oksian1 [2.3K]

Answer:

The third one

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve the following addition x + 8 =23

g100num [7]

Answer:

x= 15

Step-by-step explanation:

23-8= 15

x=15

6 0

3 years ago

Prove that x 2 + y2 - 1 is irreducible in q[ x, y].

weqwewe [10]

Suppose that the polynomial x^2+y^2-1 is not irreducible.
It means that there exists two fractions such that :
$(\frac{p}{q})^2+( \frac{s}{t} )^2 -1=0\\\text{rearranging the above formula we get:}\\p^2t^2=q^2(t^2-s^2)\\\text{since q and p are primes each other, we deduce that }\\\text{q divide t meaning that we can write }t=a\times t\text{ for an integer a}\\\text{rearranging again the formula and using our finding we get:}\\q^2s^2=a^2q^2(q^2-p^2)\\\text{Same argument as above, we deduce that q divide s.}$
We found that q divide t and q divide s, but s and t are supposed to be prime each other. It is a contradiction.
The polynomial x^2+y^2-1 is then irreducible in q[x,y]

6 0

4 years ago