The coordinates for the vertices are A(1,3), B(4,0) ,C(1,-3) ,D(-2,0) what is the length of the AB
1 answer:
Answer: 3sqrt(2)
Step-by-step explanation:
d = sqrt[(3-0)^2 + (4-1)^2]
d = sqrt[9+9]
d = sqrt(18) = 3sqrt(2)
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25=d+q
4.30= .1d + .25q
25=d+q
-17.20=-.4d+-q
7.80= .6d
d=13...... 13 DIMES
25= 13+q
12=q....... 12 QUARTERS
Answer:
it would be 5
Step-by-step explanation:
because we define 