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slamgirl [31]
3 years ago
11

HELP PLZ!

Mathematics
1 answer:
Paraphin [41]3 years ago
5 0

<u>Solution-</u>

In order to get A'B'C' from ABC we have to do two steps,

they are

1- First we need to rotate the triangle around its own vertex C (-1 , 3)

2- Then moving the triangle 4 units downwards we will get the desired triangle.

After doing the first step the new co-ordinates of A,B,C  will be,

(-2 , 4),(2 , 1) and (-1 , 3)

Then moving the triangle 4 units downward (i.e subtracting from y co-ordinate as we are moving in -ve y direction), the co-ordinates will be,

A' = (-2 , -3)

B' = (2 , -3)

C' = (-1 , -1)



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Answer:

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Step-by-step explanation:

Given:

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                                x*dv/dx = 0.5*(1/v) + 1.5*v

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                                 (2v.dv / (v^2 + 1) = dx / x  

- Integrate both sides:

                                 Ln (v^2 + 1) = Ln(x) + C

                                 v^2 + 1 = Cx

                                 v = sqrt(Cx - 1)

- Back substitution:

                                (y/x) = sqrt(Cx - 1)

                               y = x*sqrt(Cx - 1)

                         

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Determine the equation of the circle with centre (-3;5) and passing through a point (2;-9)
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Therefore, the equation of circle is: (x+3)^{2}+(y+5)^{2} = 100

<h3><u>What is a circle?</u></h3>
  • All points in a plane that are at a specific distance from a specific point, the center, form a circle. In other words, it is the curve that a moving point in a plane draws to keep its distance from a specific point constant.
  • The radius of a circle is the separation between any point on the circle and its center.
  • The radius must typically be a positive integer. Except when otherwise specified, this article discusses circles in Euclidean geometry, namely the Euclidean plane.
  • A circle, specifically, is a straightforward closed curve that separates the plane into its inner and exterior.

Here we know that(h,k) = (-3,5)but we are not given the radius.

However, we can find the radius by using the distance formula.

\sqrt{x^{2} +y^{2} }, where x=x_{1} -x_{2} and y=y_{1} -y_{2}

Putting the values, we get:

\sqrt{8^{2} +6^{2} }

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An equation of the circle with center (h,k) and radius r is

(x-h)^{2} +(y-k)^{2} = r^{2}

Now, substituting the values, we get:

(x--3)^{2} +(y-5)^{2} = 10^{2}

Therefore, the equation of circle is:

(x+3)^{2}+(y+5)^{2} = 100

Know more about circles with the help of the given link:

brainly.com/question/10618691

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