solve for "x".
what about "y"? well, y = 240 - x
HELP PLZ!
1 answer:
<u>Solution-</u>
In order to get A'B'C' from ABC we have to do two steps,
they are
1- First we need to rotate the triangle around its own vertex C (-1 , 3)
2- Then moving the triangle 4 units downwards we will get the desired triangle.
After doing the first step the new co-ordinates of A,B,C will be,
(-2 , 4),(2 , 1) and (-1 , 3)
Then moving the triangle 4 units downward (i.e subtracting from y co-ordinate as we are moving in -ve y direction), the co-ordinates will be,
A' = (-2 , -3)
B' = (2 , -3)
C' = (-1 , -1)
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solve for "x".
what about "y"? well, y = 240 - x
Answer:
See attached image
Step-by-step explanation:
This equation for a parabola is given in vertex form, so it is very simple to extract the coordinates of its vertex, by using the opposite of the number that accompanies the variable "x" in the squared expression (opposite of 2) for the vertex's x-value, and the value of the constant (-6) for the vertex's y-value.
The vertex coordinates are therefore: (-2,-6)
The equation of the axis of symmetry of the parabola is a vertical line passing through the vertex. Since all vertical lines have the shape x = constant in our case, in order to pass through (-2,-6) the vertical line is defined by the equation: x = -2.
See image attached to find the vertex drawn as a red point, and the axis of symmetry as an orange vertical line passing through it.
