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3 years ago

What is 6x - 9 = 15?

1 answer:

6 0

Add 9 to both sides and you get 6x=24 then you divide 6 from both sides to get x by its self and the final answer will be 4

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Rick bought 3 shirts for $18 each, 2 pair of socks for $3.99 a pair, and a pair of slacks, for $45.00. The sales tax is 8.5%. Ho

ivolga24 [154]

Price of 3 shirts=$18*3=$54
Price of 2 pair of socks=2*$3.99=$7.98
Price of a pair of slack=$45
Total amount- $54+$7.98+ $45-$106.98
Sales tax rate = 8.5%
8.5% of total amount-8.5% of $106.98=
(8.5/100)*106.98-9.0933
Total amount Rick paid=$106.98+9.0933=$116.0733
Regards

6 0

3 years ago

Find the value of x. If your answer is not an integer, express it in simplest radical form.

DedPeter [7]

Answer:

x = 8√5

Step-by-step explanation:

for right triangle

c^2 = a^2 + b^2

with c is the hypotenuse; a & b are the other sides

(4 + 16)^2 = (4√5)^2 + x^2

400 = 80 + x^2

x^2 = 320

x^2 = 64(5)

√x^2 = √64(√5)

x = 8√5

7 0

2 years ago

John has 48 square centimeter tiles he wants to use to

Zinaida [17]

b or the second option

The correct answer for the question that is being presented above is this one: "w(w + 2) = 48." John has 48 square centimeter tiles he wants to use to create a mosaic. He wants the mosaic to be rectangular with a length that is 2 centimeters longer than the width.

Let w = width

Let (w+2) = length

Area = w(w+2).

3 0

3 years ago

Read 2 more answers

All the fourth-graders in a certain elementary school took a standardized test. A total of 85% of the students were found to be

Aneli [31]

Answer:

There is a 2% probability that the student is proficient in neither reading nor mathematics.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a student is proficient in reading

B is the probability that a student is proficient in mathematics.

C is the probability that a student is proficient in neither reading nor mathematics.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a student is proficient in reading but not mathematics and $A \cap B$ is the probability that a student is proficient in both reading and mathematics.

By the same logic, we have that:

$B = b + (A \cap B)$

Either a student in proficient in at least one of reading or mathematics, or a student is proficient in neither of those. The sum of the probabilities of these events is decimal 1. So

$(A \cup B) + C = 1$