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Scorpion4ik [409]
4 years ago
8

The sum of three consecutive integers is -30. find the integers.

Mathematics
1 answer:
slega [8]4 years ago
5 0
Consecutive integers are one apart from each tother
they are
x,x+1,x+2

sum is -30
x+x+1+x+2=-30
3x+3=-30
minus 3 both sides
3x=-33
divide 3
x=-11

find rest
x+1=-11+1=-10
x+2=-11+2=-9

they are
-9,-10,-11
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Given:

The given sets are:

U=\{x|x\in N\text{ and }x

A=\{x|x\text{ is an odd natural number and }x

B=\{x|x\text{ is an even natural number and }x

C=\{x|x\in N\text{ and }3

To find

The set B\cap U.

Solution:

We have,

U=\{x|x\in N\text{ and }x

U=\{1,2,3,4,5,6,7,8,9\}

B=\{x|x\text{ is an even natural number and }x

B=\{2,4,6,8\}

Now, B\cap U is the set that contains all the common elements of both sets B and U.

B\cap U=\{2,4,6,8\}

B\cap U=B

Therefore, the correct option is A.

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Step-by-step explanation:

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ICE Princess25 [194]

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==>  5<em>n</em> + 10<em>d</em> = 150

Multiply both sides of the first equation by -5:

<em>n</em> + <em>d</em> = 21

==>  -5<em>n</em> - 5<em>d</em> = -105

Add the two equations together:

(5<em>n</em> + 10<em>d</em>) + (-5<em>n</em> - 5<em>d</em>) = 150 + (-105)

Notice that the terms containing <em>n</em> get eliminated and we can solve for <em>d</em> :

(5<em>n</em> - 5<em>n</em>) + (10<em>d</em> - 5<em>d</em>) = 150 - 105

5<em>d</em> = 45

<em>d</em> = 45/5 = 9

Plug this into either original equation to solve for <em>n</em>. Doing this with the first equation is easiest:

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