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EastWind [94]
3 years ago
10

Solve by completing the square with working out -6x-x^2-8

Mathematics
1 answer:
horrorfan [7]3 years ago
4 0

Answer:

x = -3 +/- sqrt(17)

Step-by-step explanation:

-6x - (x^2) - 8 = 0

-((x^2) + 6x + 8) = 0

(x^2) + 6x + 8 = 0

(x + 3)^2 - 1 = 0

(x + 3)^2 = 1

x + 3 = +/- sqrt(1)

x + 3 = +/- 1

x = -3 +/- 1

x = -4, -2

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Answer:

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x + 65 = 90

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y = 25

x = 25

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Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form. HELP PLEASE!!
Nataliya [291]

Answer:

  • Perimeter = 22*sqrt(2)
  • Area = 60.5 inches
  • D

Step-by-step explanation:

Remark

You need 2 facts.

  1. A square has 4 equal sides.
  2. It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

That means you can use the Pythagorean Theorem.

If one side of a square is a then the 1 after it is a as well.

Formula

  • a^2 + a^2 = c^2
  • 2a^2 = c^2

Givens

  • c = 11

Solution

  • 2a^2 = 11^2
  • 2a^2 = 121                    Divide by 2
  • a^2 = 121/2                  Take the square root of both sides
  • sqrt(a^2) = sqr(121/2)    
  • a = 11/sqrt(2)                Rationalize the denominator
  • a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
  • a = 11 * sqrt(2) / 2

<em><u>Perimeter</u></em>

P = 4s

  • P = 4*11*sqrt(2)/2
  • P = 44*sqrt(2)/2
  • P = 22*sqrt(2)

You don't need the area. The answer is D

<em><u>Area</u></em>

  • Area = s^2
  • Area = (11*sqrt(2)/2 ) ^2
  • Area = 121 * 2 / 4
  • Area = 60.5


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Un answerable how many friends buy tickets?
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