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Katyanochek1 [597]
3 years ago
13

What is 1.47 written as a fraction or a mixed number

Mathematics
2 answers:
dimulka [17.4K]3 years ago
6 0
<span>1.47 = 147/100 = 1 and 47/100

hope that helped 
hope thats right =D</span>
zimovet [89]3 years ago
6 0
A decimal is out of 100 so it's 147/100 and that simplified is 1 and 47/100.
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94.2 is the circumference
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The figure shows the graphs of the cost and revenue functions for a company that manufactures and sells small radios. More than
Lyrx [107]
ANSWER

The company must produce and sell more than 700 radios to have a profit.

EXPLANATION

The revenue function is

R(x)=40x
and the cost function is

C(x)=5,600+32x


The company will break even when total revenue is equal to the total cost.


This implies that,


40x =5,600+32x

We group similar terms to get,


40x - 32x = 5600

This simplifies to,

8x = 5600

Divide both sides by 8 to get,


x =  \frac{5600}{8}


x = 700


The company breaks even by producing and selling 700 radios.

The company must produce and sell more than 700 radios to have a profit.
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3 years ago
You have 18 pictures to paste to a poster. You want to arrange them on the poster in rows so that there are an equal number of p
Lesechka [4]

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no idea too hard but try  math          way

Step-by-step explanation:

7 0
2 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

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Answer:

8. A, B

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Step-by-step explanation:

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