The length of a rectangular garden is 6 m greater than the width. The area of the garden is nbsp 72 m squared . Find the dimensi
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Answer:
Total Perimeter of Triangle: 6.33 + 6 + 2= 14.33
Step-by-step explanation:
First of all, to find the perimeter of a triangle you need to know the measurements of all three sides. When you need to find the measurement of the slanted side, ( or hypotenuse), you need to use the Pythagorean Theorem.
Then, we insert the numbers:
= 4
= 36
So, = 40 or
But wait, the number is is still squared, so the square root of 40, is 6.32455532. ( The number rounded is 6.33, or in tenths, 6.3 )
Finally, we add the measurements of all the sides on the triangle to find the perimeter, which is:
14.33 or 14.3
Answer:
Each adult male has a 5.05% probability of having a hip width greater than 16.2 inches.
There is a 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by
After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.
In this problem
Assume that adult men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1.1 inches. This means that .
What is the probability that any one of those adult male will have a hip width greater than 16.2 inches?
For each one of these adult males, the probability that they have a hip width greater than 16.2 inches is 1 subtracted by the pvalue of Z when X = 16.2. So:
has a pvalue of 0.9495.
This means that each male has a 1-0.9495 = 0.0505 = 5.05% probability of having a hip width greater than 16.2 inches.
For the average of the sample
What is the probability that the 110 adult men will have an average hip width greater than 16.2 inches?
Now, we need to find the standard deviation of the sample before using the zscore formula. That is:
.
Now
has a pvalue of 0.9999.
This means that there is a 1-0.9999 = 0.0001 = 0.01% probability that the 110 adult men will have an average hip width greater than 16.2 inches.