Answer:
35 and 55
Step-by-step explanation:
x+(2×-15)=90
3x-15=90
3x=105
x=35
other angle is 35×2-15=55
Answer:
x = 2/5
General Formulas and Concepts:
Order of Operations: BPEMDAS
Step-by-step explanation:
<u>Step 1: Write equation</u>
5x = 2
<u>Step 2: Solve for </u><em><u>x</u></em>
- Divide both sides by 5: x = 2/5
<u>Step 3: Check</u>
<em>Plug in x to verify it's a solution</em>.
- Substitute: 5(2/5) = 2
- Multiply: 10/5 = 2
- Divide: 2 = 2
Answer: 316.52
Step-by-step explanation:
77.2*4.1 = 316.52
If you have problems with multiplying decimals:
Multiply the numbers just as if they were whole numbers.
1.Line up the numbers on the right - do not align the decimal points.
2.Starting on the right, multiply each digit in the top number by each digit in the bottom number, just as with whole numbers.
3.Add the products.
<span>(3y*5b)*10 = __(5b*10)
</span>15yb *10 = __(5b*10)
150yb = 3y(50b)= 150yb
Do you have any questions?
3y is the answer<span>.</span>
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
__
a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
