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borishaifa [10]
3 years ago
10

Megan bought 50 beads for $9.95. She received a 10% discount, and she paid a sales tax of 6%. how much did she pay for the beads

?
Mathematics
1 answer:
docker41 [41]3 years ago
8 0
I think the answer 10.100 i really dont know
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If y is proportional to x and y = -15 when x = -20, what is the value of x when y = 12?
alexandr402 [8]
Maybe i have that you wanted We can represent the situation like that: Y=-15 and x=-20 Then When y=12 x=? We make x(The unknown) *-15=12*(-20) We have an simple équation to solve Thus x=(12*(-20))/-15 X=16
7 0
3 years ago
Read 2 more answers
What is the converse of ​r->(~q v p)
alexira [117]

Answer:

 r =>  (\neg q \ \lor p)  \ \equiv  \  q \ \land \ \neg p => \neg r

Step-by-step explanation:

In general, remember that the converse of    a => b       is     \neg b  =>   \neg a , therefore in this case  a = r   \ \ ,  b = \neg q \ \lor p

so   r =>  (\neg q \ \lor p)  \ \equiv  \  q \ \land \ \neg p => \neg r

   

8 0
3 years ago
Which of the following pairs of functions are inverses of each other?
AnnyKZ [126]

Answer:

Step-by-step explanation:

Rearrange each function to solve for x.

Switch x and y,

The resulting equation is the inverse function.

A:

f(x) = y = 5+x

x = y-5

y = x-5

f⁻¹(x) = x-5

g(x) = 5-x ≠ f⁻¹(x)

g(x) is not the inverse of f(x).

:::::

B:

f(x) = y = 2x-9

x = (y+9)/2

y = (x+9)/2

f⁻¹(x) = (x+9)/2

g(x) = (x+9)/2 = f⁻¹(x)

g(x) is the inverse of f(x).

:::::

C:

f(x) = y = 2/x - 6

x = 2/(y+6)

y = 2/(x+6)

f⁻¹(x) = 2/(x+6)

g(x) = (x+6)/2 ≠ f⁻¹(x)

:::::

D:

f(x) = y = x/3 + 4

x = 3y - 12

y = 3x - 12

f⁻¹(x) = 3x - 12

g(x) = 3x - 4 ≠ f⁻¹(x)

g(x) is not the inverse of f(x).

4 0
2 years ago
is <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3to%20%5C%3A%20the%20%5C%3A%20power%20%5C%3A%20of%20%5C%3A%20100%7D%7B3to%20%5
Norma-Jean [14]

Remember the laws of exponents:

\frac{a^n}{a^m}=a^{n-m}

Then:

\begin{gathered} \frac{3^{100}}{3^{99}}=3^{100-99} \\ =3^1 \\ =3 \end{gathered}

Therefore:

\frac{3^{100}}{3^{99}}=3

7 0
1 year ago
QUESTION IN PHOTO, HELP ASAP
Luba_88 [7]
I don’t get the question? What are you trying to find?
6 0
3 years ago
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