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scZoUnD [109]
2 years ago
13

Find the indicated probability. round to three decimal places. a test consists of 10

Mathematics
1 answer:
Charra [1.4K]2 years ago
7 0

To answer this problem, we use the binomial distribution formula for probability:

P (x) = [n! / (n-x)! x!] p^x q^(n-x)

Where,

n = the total number of test questions = 10

<span>x = the total number of test questions to pass =   >6</span>

p = probability of success = 0.5

q = probability of failure = 0.5

Given the formula, let us calculate for the probabilities that the student will get at least 6 correct questions by guessing.

P (6) = [10! / (4)! 6!] (0.5)^6 0.5^(4) = 0.205078

P (7) = [10! / (3)! 7!] (0.5)^7 0.5^(3) = 0.117188

P (8) = [10! / (2)! 8!] (0.5)^8 0.5^(2) = 0.043945

P (9) = [10! / (1)! 9!] (0.5)^9 0.5^(1) = 0.009766

P (10) = [10! / (0)! 10!] (0.5)^10 0.5^(0) = 0.000977

Total Probability = 0.376953 = 0.38 = 38%

<span>There is a 38% chance the student will pass.</span>

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Brilliant_brown [7]

Answer:

r = 4

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

-5 + 22 = r - 4 + 3r + 5

<u>Step 2: Solve for </u><em><u>r</u></em>

  1. Combine like terms:                    17 = 4r + 1
  2. Subtract 1 on both sides:             16 = 4r
  3. Divide 4 on both sides:               4 = r
  4. Rewrite:                                        r = 4

<u>Step 3: Check</u>

<em>Plug in r to verify it's a solution.</em>

  1. Substitute:                    -5 + 22 = 4 - 4 + 3(4) + 5
  2. Add/Subtract:               17 = 3(4) + 5
  3. Multiply:                        17 = 12 + 5
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Step-by-step explanation:

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masha68 [24]

Answer:

(5,-5)

Step-by-step explanation:

<u>Eliminate</u><u> </u><u>y-term</u>

(2x + 5x) + ( - 3y + 3y) = 25 + 10 \\ 7x = 35 \\ x =  \frac{35}{7}  \\  x = 5

We can eliminate x-term but for this system of equations, eliminating y-term is faster.

<u>Substitute</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>in</u><u> </u><u>any</u><u> </u><u>given</u><u> </u><u>equations</u><u>.</u>

I will choose to substitute in the first equation.

2x - 3y = 25 \\ 2(5) - 3y = 25 \\ 10 - 3y = 25 \\ 10 - 25 = 3y \\  - 1 5 = 3y \\ 3y  =  - 15 \\ y =  - 5

<u>Answer</u><u> </u><u>Check</u>

Substitute both x-value and y-value in any given equations

2x - 3y = 25 \\ 2(5) - 3( - 5) = 25 \\ 10 + 15 = 25 \\ 25 = 25

The equation is true. (<em>It</em><em> </em><em>is</em><em> </em><em>better</em><em> </em><em>to</em><em> </em><em>check</em><em> </em><em>both</em><em> </em><em>the</em><em> </em><em>answer</em><em> </em><em>for</em><em> </em><em>both</em><em> </em>equation.)

Thus the answer is (5,-5)

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