Answer is option 4. working out attached
hope it helps :)
Answer:
1:15
Step-by-step explanation:
there are 120 quarters in 30 dollars
so 8:120
divide both by 8
1:15
Answer:
Step-by-step explanation:
14 - If you add all she spent such as (1.95,30.00,7.50) then add it to what she has left over. You get $77.65
16- (63 x 2)+63+6=195
If x^2+bx+16 has at least one real root, then the equation x^2+bx+16=0 has at least one solution. The discriminant of a quadratic equation is b^2-4ac and it determines the nature of the roots. If the discriminant is zero, there is exactly one distinct real root. If the discriminant is positive, there are exactly two roots. The discriminant of <span>x^2+bx+16=0 is b^2-4(1)(16). The inequality here gives the values of b where the discriminant will be positive or zero:
b^2-4(1)(16) ≥ 0
</span><span>b^2-64 ≥ 0
(b+8)(b-8) </span><span>≥ 0
The answer is that all possible values of b are in the interval (-inf, -8]∪[8,inf) because those are the intervals where </span>(b+8)(b-8) is positive.
Answer:
2u + v - 4w = <40 , -4>
6u - 8v = <-78 , 58>
4v - 7w = <101 , -36>
11u + 3w = <-88 , 89>
Step-by-step explanation:
* Lets find the value of each operation to find its resultant vector
# 2u + v - 4w
∵ u = <-5 , 7>
∴ 2u = <-10 , 14>
∵ v = <6 , -2>
∵ w = <-11 , 4>
∴ 4w = <-44 , 16>
∴ 2u + v - 4w = <-10 + 6 - -44 , 14 + -2 - 16>
∴ 2u + v - 4w = <40 , -4>
# 6u - 8v
∵ u = <-5 , 7>
∴ 6u = <-30 , 42>
∵ v = <6 , -2>
∵8v = <48 , -16>
∴ 6u - 8v = <-30 - 48 , 42 - -16>
∴ 6u - 8v = <-78 , 58>
# 4v - 7w
∵ v = <6 , -2>
∴ 4v = <24 , -8>
∵ w = <-11 , 4>
∴ 7w = <-77 , 28>
∴ 4v - 7w = <24 - -77 , -8 - 28>
∴ 4v - 7w = <101 , -36>
# 11u + 3w
∵ u = <-5 , 7>
∴ 11u = <-55 , 77>
∵ w = <-11 , 4>
∴ 3w = <-33 , 12>
∴ 11u + 3w = <-55 + -33 , 77 + 12>
∴ 11u + 3w = <-88 , 89>
