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CaHeK987 [17]
3 years ago
13

Sue buys a certain brand of cereal that costs $12 per box. Sue changes to a super-saving brand of the same size. The equation sh

ows the price, y, as a function of the number of boxes, x, for the new brand.
y = 8x

Part A: How many more dollars is the price of a box of Sue's original brand of cereal than the price of a box of the super-saving brand? Show your work.

Part B: How much money does Sue save each month with the change in cereal brand if she buys 4 cereal boxes each month? Show your work. (10 points)
Mathematics
2 answers:
Mashcka [7]3 years ago
7 0
Part a: the first cereal is y=12x and the second one is y=8x so they are $4 apart.
part b: y=12*4 and y=8*4 is $16  apart so she will save $16 each month.
julia-pushkina [17]3 years ago
7 0

Answer:

part A : $4

part B : $16

Step-by-step explanation:

Sue buys a certain brand of cereal that costs = $12 per box.

She changes to a super-saving brand of the same size.

The equation showing price y as a function of the number of boxes, x is for the new brand.

y = 8x

for x = 1, y = 8

So for 1 box super-saver cereal brand costs $8.00

Part A. - So saving per box = 12 - 8 = $4

Part B. - Money saved in 1 box = $4

Therefore, money saved in 4 boxes = 4 × 4 = $16

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Select all the statements that are true for the following systems of equations
Aleks [24]

Answer:

A. System C simplifies to 2x - 3y = 4 and 4x - y = 54 by dividing the second equation by three (3).

B. Systems A and C have the same solutions.

C. Systems A and B have different solutions.

Step-by-step explanation:

Given the following system of equations;

<em><u>System A</u></em>

2x - 3y = 4  .....equation 1

4x - y = 18  .......equation 2

We would solve the above equations using the elimination method;

Multiplying eqn 1 by 2;

2*(2x) - 2*(3y) = 4*2

4x - 6y = 8  ...... equation 3

Subtracting eqn 2 from eqn 3;

(4x - 4x) + (-6y - (-y)) = 8 - 18

0 + (-6y + y) = -10

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5y = 10

y = \frac {10}{5}

y = 2

To find the value of x;

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2x - 3(2) = 4

2x - 6 = 4

2x = 4 + 6

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x = \frac {10}{2}

x = 5

<em><u>Solutions (x, y) = (5, 2)</u></em>

<u><em>System B</em></u>

3x - 4y = 5  ..... equation 1

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We would solve the equations using substitution method;

Substituting eqn 2 into eqn 1, we have;

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To find the value of y;

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<u><em>Solutions (x, y) = (-1, -2)</em></u>

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2x - 3y = 4  ..... equation 1

12x - 3y = 54  ...... equation 2

We would solve the above equations using the elimination method;

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2x - 3y = 4

2(5) - 3y = 4

10 - 3y = 4

3y = 10 - 4

3y = 6

y = \frac {6}{3}

y = 2

<u><em>Solutions (x, y) = (5, 2)</em></u>

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