I need help with number 17

Mathematics

1 answer:

zimovet [89]2 years ago

7 0

Answer:

3 planes parallel to FL is EK, CI , BH, AJ

Because, this is prism in which all length segments should be equal .

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A car was sold in 1990. The value of the car

PolarNik [594]

Answer:

i believe it is 7748.406

8 0

2 years ago

A test-preparation company advertises that its training program raises SAT scores by an average of at least 30 points. A random

aniked [119]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu \geq$ 30 points

Alternate Hypothesis, $H_A$ : $\mu$ < 30 points

(b) Type I error is that we conclude that test-takers who had completed the training showed a mean increase smaller than 30 points but in actual, the program raises SAT scores by an average of at least 30 points.

Step-by-step explanation:

We are given that a test-preparation company advertises that its training program raises SAT scores by an average of at least 30 points.

A random sample of test-takers who had completed the training showed a mean increase smaller than 30 points.

Let $\mu$ = average SAT score.

(a) So, Null Hypothesis, $H_0$ : $\mu \geq$ 30 points

Alternate Hypothesis, $H_A$ : $\mu$ < 30 points

Here, the null hypothesis states that the training program raises SAT scores by an average of at least 30 points.

On the other hand, the alternate hypothesis states that test-takers who had completed the training showed a mean increase smaller than 30 points.

(b) Type I error states the probability of rejecting the null hypothesis given the fact that null hypothesis is true.

According to the question, the Type I error is that we conclude that test-takers who had completed the training showed a mean increase smaller than 30 points but in actual, the program raises SAT scores by an average of at least 30 points.

The consequence of a Type I error is that we conclude the test-takers have low SAT scores but in actual they have an SAT score of at least 30 points.

7 0

3 years ago

Determine whether the series is absolutely convergent 1-(1*3/3! (1*3*5/5!-（3*5*7）

DENIUS [597]

It's not clear what your series is, so I'm going to take a wild guess on what it is you mean:

$1-\dfrac{1\times3}{3!}+\dfrac{1\times3\times5}{5!}-\dfrac{1\times3\times5\times7}{7!}+\cdots$
$=\displaystyle\sum_{n=1}^\infty\frac{(-1)^{n-1}}{(2n-1)!}\prod_{k=1}^n(2k-1)$

For the sum to be absolute convergent, the sum of the absolute value of the summand must converge, so you are really examining the convergence of

$\displaystyle\sum_{n=1}^\infty\frac1{(2n-1)!}\prod_{k=1}^n(2k-1)$

This is easily checked with the ratio test:

$\displaystyle\lim_{n\to\infty}\left|\frac{\displaystyle\dfrac1{(2(n+1)-1)!}\prod_{k=1}^{n+1}(2k-1)}{\displaystyle\dfrac1{(2n-1)!}\prod_{k=1}^n(2k-1)}\right|=\lim_{n\to\infty}\left|\frac{\dfrac{1\times3\times5\times\cdots\times(2n-1)\times(2n+1)}{(2n+1)!}}{\dfrac{1\times3\times5\times\cdots\times(2n-1)}{(2n-1)!}}\right|$
$\displaystyle=\lim_{n\to\infty}\left|\frac{\dfrac{2n+1}{(2n+1)(2n)}}{\dfrac11}\right|=\lim_{n\to\infty}\dfrac1{2n}=0$

Since $\sum|a_n|$ converges by the ratio test, the series $\sum a_n$ converges absolutely.