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pickupchik [31]
4 years ago
7

(01.05 LC)

Computers and Technology
2 answers:
liq [111]4 years ago
8 0
Their answer is known as an input, because they are saying what they know/think. Sorry if this didnt help have a nice day though^^
andriy [413]4 years ago
7 0
The answer is input! because the input is what the user enters, the output is what comes out from that, and the text and value aren’t related to the user
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igor_vitrenko [27]
B. Television. It provided <span>instant communication and information to a massive audience for the first time in 1927.

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4 0
3 years ago
Read 2 more answers
Assignment Background Video games have become an outlet for artists to express their creative ideas and imaginations and a great
Sphinxa [80]

Answer:

Code

import csv

def open_file():

try:

fname=input("Enter the filename to open (xxx.yyy): ")

fp=open(fname,encoding='utf-8')

return fp

except FileNotFoundError:

print("File not found! Please Enter correct filename with extension")

return open_file()

def read_file(fp):

fields = []

rows = []

csvreader = list(csv.reader(fp))

# skiped 1 row because it contains field name

fields = csvreader[0]

D1={}

D2={}

D3={}

# accessing the data of csv file

for line in csvreader[1:]:

name = line[0].lower().strip()

platform = line[1].lower().strip()

if line[2]!='N/A':

year = int(line[2])

else:

year=line[2]

genre = line[3].lower().strip()

publisher = line[4].lower().strip()

na_sales = float(line[5])

eur_sales = float(line[6])

jpn_sales = float(line[7])

other_sales = float(line[8])

global_sales=(na_sales+eur_sales+jpn_sales+other_sales)*1000000

if name not in D1:

D1[name]=[]

D1[name].append((name, platform, year, genre, publisher,global_sales))

if genre not in D2:

D2[genre]=[]

D2[genre].append((genre, year, na_sales, eur_sales,jpn_sales, other_sales, global_sales))

if publisher not in D3:

D3[publisher]=[]

D3[publisher].append((publisher, name, year, na_sales,eur_sales, jpn_sales, other_sales, global_sales))

# sorting

temp={}

# sorting keys

for Keys in sorted (D1) :

ls=D1[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D1=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D2) :

ls=D2[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

temp[Keys]=ls

D2=temp.copy()

temp={}

# sorting keys

for Keys in sorted (D3) :

ls=D3[Keys]

ls=sorted(ls,key=lambda x: x[-1]) # sorting values

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D3=temp.copy()

return D1,D2,D3

 

def main():

fp=open_file()

D1,D2,D3=read_file(fp)

# displaying the row_count in dictionaries

cnt=0

for d in D1:

cnt+=1

print(cnt)

print("\n\n=============================================\n\n")

cnt=0

for d in D2:

cnt+=1

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for d in D3:

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if __name__=="__main__":

main()

Explanation:

see code and see output attached

7 0
3 years ago
Create a class called Circle, which has (i) an attribute radius, (ii) a method that returns the current radius of a circle objec
nadya68 [22]

Answer:

Explanation:

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class Circle {

   double radius;

   public Circle(double radius) {

       this.radius = radius;

   }

   public double getRadius() {

       return radius;

   }

   public void resetRadius() {

       radius = 0;

   }

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vlada-n [284]

Answer:

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6 0
2 years ago
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lilavasa [31]

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4 years ago
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