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Viktor [21]
3 years ago
12

I’ll mark Brainly! That is if you want it, I put a picture help me out please!

Mathematics
1 answer:
Tema [17]3 years ago
3 0

Answer:

a=-4 b=-2 c=-1 d=1 e=2

Step-by-step explanation:

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Exercise 11.21) Many smartphones, especially those of the LTE-enabled persuasion, have earned a bad rap for exceptionally bad ba
stiv31 [10]

Answer:

Step-by-step explanation:

Hello!

The researcher suspects that the battery life between charges for the Motorola Droid Razr Max differs if its primary use is talking or if its primary use is for internet applications.

Since the means for talk time usage (20hs) is greater than the mean for internet usage (7hs) the main question is if the variance in hours of usage is also greater when the primary use is talk time.

Be:

X₁: Battery duration between charges when the primary usage of the phone is talking. (hs)

n₁= 12

X[bar]₁= 20.50 hs

S₁²= 199.76hs² (S₁= 14.13hs)

X₂: Battery duration between charges when the primary usage of the phone is internet applications.

n₂= 10

X[bar]₂= 8.50

S₂²= 33.29hs² (S₂= 5.77hs)

Assuming that both variables have a normal distribution X₁~N(μ₁;σ₁²) and X₂~N(μ₂; σ₂²)

The parameters of interest are σ₁² and σ₂²

a) They want to test if the population variance of the duration time of the battery when the primary usage is for talking is greater than the population variance of the duration time of the battery when the primary usage is for internet applications. Symbolically: σ₁² > σ₂² or since the test to do is a variance ratio: σ₁²/σ₂² > 1

The hypotheses are:

H₀: σ₁²/σ₂² ≤ 1

H₁: σ₁²/σ₂² > 1

There is no level of significance listed so I've chosen α: 0.05

b) I've already calculated the sample standard deviations using a software, just in case I'll show you how to calculate them by hand:

S²= \frac{1}{n-1}*[∑X²-(∑X)²/n]

For the first sample:

n₁= 12; ∑X₁= 246; ∑X₁²= 7240.36

S₁²= \frac{1}{11}*[7240.36-(246)²/12]= 199.76hs²

S₁=√S₁²=√199.76= 14.1336 ≅ 14.13hs

For the second sample:

n₂= 10; ∑X₂= 85; ∑X₂²= 1022.12

S₂²= \frac{1}{9}*[1022.12-(85)²/10]= 33.2911hs²

S₂=√S₂²=√33.2911= 5.7698 ≅ 5.77hs

c)

For this hypothesis test, the statistic to use is a Snedecors F:

F= \frac{S_1^2}{S_2^2} *\frac{Sigma_1^2}{Sigma_2^2} ~~F_{n_1-1;n_2-1}

This test is one-tailed right, wich means that you'll reject the null hypothesis to big values of F:

F_{n_1-1;n_2-1; 1-\alpha }= F_{11;9;0.95}= 3.10

The rejection region is then F ≥ 3.10

F_{H_0}= \frac{199.76}{33.29} * 1= 6.0006

p-value: 0.006

Considering that the p-value is less than the level of significance, the decision is to reject the null hypothesis.

Then at a 5% level, there is significant evidence to conclude that the population variance of the duration time of the batteries of Motorola Droid Razr Max smartphones used primary for talk is greater than the population variance of the duration time of the batteries of Motorola Droid Razr Max smartphones used primary for internet applications.

I hope this helps!

8 0
3 years ago
Which equation matches the graph of the greatest integer function given below?? help pleaze
Alex787 [66]
The correct answer is C
4 0
4 years ago
Read 2 more answers
A sample of students is taken from the school's A honor roll. The school estimates that there are actually 360 students on the A
aliya0001 [1]

Answer:

360 - Y

Step-by-step explanation:

From the information provided in the question, we will understand that the question lacks detailed information.

Given that:

The total number of actual students on the A honor roll = 360

To find the number of students on the A honor roll of 8th graders;

Let denote Y to represent the total number of students who exist on the A honor roll except for the 8th graders.

Then:

The number of 8th graders = all number of students on are on the A honor roll - Y

The number of 8th graders = 360 - Y

If Y is known, then the number of the 8th graders can be fully determined.

5 0
3 years ago
Can you please help me with this all I'm asking is just help for one question . ​
shutvik [7]
The value of “u” is 32°.
5 0
3 years ago
Solve the following x/5=10<br>​
sergey [27]

Answer:

x = 50

Step-by-step explanation:

x/5 = 10

Multiply both sides of the equation by 5.

5(x/5) = 5(10)

x = 5(10)

x = 50

The value of x is 50.

6 0
3 years ago
Read 2 more answers
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