Answer:
Triangle P and Triangle Q are mathematically similar shapes (?).
Step-by-step explanation:
Hi, so the question asks which statement is true, given the following information, but you haven't written what statements we can choose from.
After reading the information, we can see that Triangle Q is the same shape as Triangle P but just larger.
I'm assuming that one of the statements given is about Triangle P and Triangle Q being mathematically similar shapes?
If you need to show your working out, here it is:
18 ÷ 6 = 3
24 ÷ 8 = 3
30 ÷ 10 = 3
All the angles are the same.
This means that the length scale factor is +3 from Triangle P to Triangle Q, the area scale factor is +9 (because 3 x 3 = 9) from Triangle P to Triangle Q, and that the two shapes are mathematically similar.
*DISCLAIMER* The majority of question askers on Brainly seem to be from the US, and I'm not, so the way I work things out / the mathematical terms I use might be different. Sorry!
Hope this helped anyway!
Bluey :)
Answer:
350 girls
Step-by-step explanation:
So,
The secret to solving problems with ratios is to find the value of one unit.
5:7 = 12 units total
To find one unit, divide the total number of students by the total number of units.
600/12 = a
Simplify
50/1 = a
50 = a
The value of each unit is 50.
Now, multiply the units by the numbers in the ratio.
50(5) = b
250 = boys
50(7) = x
350 = x
There are 350 girls.
Answer:
Sam is incorrect
Step-by-step explanation:
We can calculate the lengths of the diagonals using Pythagoras' identity.
The diagonals divide the rectangle and square into 2 right triangles.
Consider Δ SRQ from the rectangle
SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )
SQ =
≈ 13.4 in ( to 1 dec. place )
Consider Δ ONM from the square
OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )
OM =
≈ 8.5 in ( to 1 dec. place )
Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4
Then diagonal OM is not twice the length of diagonal SQ
Answer:
Step-by-step explanation:
f(x) = -8x + 20
f(-1) = -8* -1 + 20 = 8+20 =28
5 - 2[f(-1)] = 5 - 2*28 = 5 - 56 = -51