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Ede4ka [16]
2 years ago
13

Explain how do you know that in × 6,273 =6,273 the ? will be 1

Mathematics
1 answer:
kati45 [8]2 years ago
7 0
Are you asking that in the equation X*6,273=6,273 X will be one? If so you can know this because 1 times anything equals itself, one is the only number to do this, an example is 1 times 2 equals 2. what ever number that equals x must be multiplied by 6,273 and still equal 6,273. In multiplication 1 acts like zero dose in addition. If you have 5 cookies and you don't take away any (5-0) then you will still have 5 cookies. It would be silly to say you now have three cookies because we didn't take away any.
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Step-by-step explanation:

\mathsf{Given :\;\dfrac{{sec}^2\theta - co{sec}^2\theta}{{sec}^2\theta + co{sec}^2\theta}}

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\bigstar\;\;\textsf{We know that : \large\boxed{\mathsf{co{sec}\theta = \dfrac{1}{sin\theta}}}}

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\mathsf{\implies \dfrac{sin^2\theta - cos^2\theta}{sin^2\theta + cos^2\theta}}

Taking sin²θ common in both numerator & denominator, We get :

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\mathsf{\implies \dfrac{1 - \left(\dfrac{1}{\sqrt{5}}\right)^2}{1 + \left(\dfrac{1}{\sqrt{5}}\right)^2}}

\mathsf{\implies \dfrac{1 - \dfrac{1}{5}}{1 + \dfrac{1}{5}}}

\mathsf{\implies \dfrac{\dfrac{5 - 1}{5}}{\dfrac{5 + 1}{5}}}

\mathsf{\implies \dfrac{5 - 1}{5 + 1}}

\mathsf{\implies \dfrac{4}{6}}

\mathsf{\implies \dfrac{2}{3}}

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