Question

A publisher reports that 37% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 350 found that 30% of the readers owned a laptop. Make the decision to reject or fail to reject the null hypothesis at the 0.02 level.

Answer 1

Answer:

0.1470

Step-by-step explanation:

Hypothesis : H_0:=0.37 Vs H_1:$\neq[\tex] 0.30The test statistic under H_o is given by ,Z=[tex]\frac{p-p_0}{\sqrt{(p_0 q_0)/n}}\rightarrow N(0,1)$

=$\frac{0.30-0.37}{\sqrt{0.37\times0.63/100}}$

=$\frac{-0.07}{\sqrt{0.00233}}$

=-1.45

P value : P value = 2*P ( Z > | Z cal | )

= 2*P ( Z > 1.45 )

= 2*0.07352

= 0.14704