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2 years ago

The data below represents the number of minutes Jake and Sarah spent doing chores

1 answer:

8 0

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The median number of minutes for Jake and Sarah are equal, but the mean numbers are different.

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For this, you never said the choices, but I’ve done this before, so I’m going to use the answer choices I had, and hopefully they are right.

Our choices are -

• The median number of minutes for Jake is higher than the median number of minutes for Sarah.

• The mean number of minutes for Sarah is higher than the mean number of minutes for Jake.

• The mean number of minutes for Jake and Sarah are equal, but the median number of minutes are different.

• The median number of minutes for Jake and Sarah are equal, but the mean number of minutes are different.

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So to answer the question, we neee to find the median and mean for each data set, so -

Jack = [90 median] [89.6 mean]
Sarah = [90 median] [89.5 mean]

We can clearly see the median for both is 90, so we can eliminate all the choices that say they are unequal.

We can also see that Jack has a higher mean (89.6) compared to Sarah (89.5).

We can eliminate all the choices that don’t imply that too.

That leaves us with -

• The median number of minutes for Jake and Sarah are equal, but the mean number of minutes are different.

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Determine which function has the greatest rate of change over the interval [0, 2].

ruslelena [56]

Remember that the average rate of change of a function over an interval is the slope of the straight line connecting the end points of the interval. To find those slopes, we are going to use the slope formula: $m= \frac{y_{2}-y_{1}}{x_2-x_1}$

Rate of change of $a$ :
From the graph we can infer that the end points are (0,1) and (2,4). So lets use our slope formula to find the rate of change of $a$ :
$m= \frac{y_{2}-y_{1}}{x_2-x_1}$
$m= \frac{4-1}{2-0}$
$m= \frac{3}{2}$
$m=1.5$
The average rate of change of the function $a$ over the interval [0,2] is 1.5

Rate of change of $b$ :
Here the end points are (0,0) and (2,2)
$m= \frac{2-0}{2-0}$
$m= \frac{2}{2}$
$m=1$
The average rate of change of the function $b$ over the interval [0,2] is 1

Rate of change of $c$ :
Here the end points are (0,-1) and (2,0)
$m= \frac{0-(-1)}{2-0}$
$m= \frac{1}{2}$
$m=0.5$
The average rate of change of the function $c$ over the interval [0,2] is 0.5

Rate of change of $d$ :
Here the end points are (0,0.5) and (2,2.5)
$m= \frac{2.5-0.5}{2-0}$
$m= \frac{2}{2}$
$m=1$
The average rate of change of the function $d$ over the interval [0,2] is 1

We can conclude that the <span>function that has the greatest rate of change over the interval [0, 2] is the function a.</span>

4 0

3 years ago

Thomas runs 34 of a mileevery day for 5 days. Howfar has he run total?

STALIN [3.7K]

Guven:

Miles per day = 34 miles

Number of days = 5 days

To find the total distance(miles), we have:

Total distance = distance covered per day x Number per days

= 34 x 5 = 170 miles

Therefore, the total distance he has covered is 170 miles

ANSWER:

170 miles

4 0

1 year ago

What is the best estimate for the number of people in line at 7.A.M

Keith_Richards [23]

We have been given the equation

$y=-5.131x^2+31.821x-3.333$

It represents the number of people standing to catch a commuter train x hours after 5 A.M.

Now, in order to find the number of people in line at 7 a.m. , we need to substitute x= 2 in the above equation.

$y(2)=-5.131(2)^2+31.821(2x)-3.333\\y(2)= 39.785 \approx 40$

Therefore, the number of people in the line at 7 a.m. is 40

D id the correct option.

5 0

3 years ago

This summer, Nora spent 8 days visiting her aunt and 2 weeks visiting her grandmother. In all, how many days did she spend visit

balandron [24]

Answer:

Step-by-step explanation:

1 week = 7 days

2 weeks= 14 days

14+8=22

8 0

3 years ago

Plz, answer the question in the photo.

Mamont248 [21]

Answer:

2/5

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers