Its 9 because it includes f(x)
Answer:
Step-by-step explanation:
subtract 9 from both sides
x=3
The given quadratic describes a parabola that opens upward. Its one absolute extreme is a minimum that is found at x = -3/2. The value of the function there is
(-3/2 +3)(-3/2) -1 = -13/4
The one relative extreme is a minimum at
(-1.5, -3.25).
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For the parabola described by ax² +bx +c, the vertex (extreme) is found where
x = -b/(2a)
Here, that is x=-3/(2·1) = -3/2.
Answer:
y = -3x - 16
Step-by-step explanation:
Point-slope form: y - y1 = m(x - x1)
Given: y - 2 = -3(x + 6)
Slope-intercept form: y = mx + b
To write the equation in slope-intercept form, we need to know the slope(m) and the y-intercept(b). By looking at the given equation, we can see that the slope is -3. We are also given the value of one point: (-6, 2).
To find the y-intercept, input the given values of the slope and the point into the equation format and solve for b:
y = mx + b
2 = -3(-6) + b
2 = 18 + b
Subtract 18 from both sides of the equation to isolate b:
2 - 18 = 18 - 18 + b
-16 = b
The y-intercept is -16.
Now that we know the slope and the y-intercept, we can write the equation:
y = -3x - 16