All categories

3 years ago

F(7)=3/x+2-squar root x-3

Mathematics

1 answer:

leonid [27]3 years ago

8 0

Insert x = 7
so 3/(7+2) - sqr (7-3)
=3 / (9) - sqr (4)
= 1/3 - 2
=1/3 - 6/3
= -5/3

You might be interested in

(1,4) and m= -2 write in line slope intercept form help pls

nevsk [136]

Y=-2x+6 hope this helps

8 0

3 years ago

Read 2 more answers

find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$

hope helpful :D

6 0

2 years ago

Consider the function, f(x) = 3x - 3. Determine the asymptote for the function f(x).

Natali [406]

Answer:

Y= 1

Step-by-step explanation:

Given the expression f(x) = 3x - 3.

To solve for the asymptote y

Firstly we need to solve for x

3x-3=0

3x=3

x= 3/3

x=1

Hence the asymptote of the function y=1

5 0

3 years ago

Greg is 10 years older than his brother gabe. He is also 3 times as old as gabe. How old is Greg?

Mashcka [7]

Answer: 30 i think 10x3=30

Step-by-step explanation:

5 0

3 years ago

Which best describes the solution for the system of linear equations graphed below?

Shalnov [3]

Answer:

D is correct Answer. Parallel line on graph means infinity many solutions.

6 0

3 years ago