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jek_recluse [69]
3 years ago
13

F(7)=3/x+2-squar root x-3

Mathematics
1 answer:
leonid [27]3 years ago
8 0
Insert x = 7
so 3/(7+2) - sqr (7-3)
=3 / (9) - sqr (4)
= 1/3 - 2
=1/3 - 6/3
= -5/3
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A car leaving a stop sign accelerates constantly from a speed of 0 feet per second to reach a speed of 44 feet per second. The d
Nikolay [14]

Answer:

Option C.

Step-by-step explanation:

The distance of the car from the stop sign, d , in feet, at time t , in seconds, can be found using the equation

d=1.1t^2

The average rate of change of a function f(x) on [a,b] is

m=\dfrac{f(b)-f(a)}{b-a}

We need to find the average speed of the car, in feet per second, between t=2 and t=5.

At t=2,

d=1.1(2)^2=4.4

At t=5,

d=1.1(5)^2=27.5

The average speed of the car, in feet per second, between t=2 and t=5 is

\text{Average speed}=\dfrac{d(5)-d(2)}{5-2}

\text{Average speed}=\dfrac{27.5-4.4}{3}

\text{Average speed}=\dfrac{23.1}{3}

\text{Average speed}=7.7

The average speed of the car, in feet per second, between t=2 and t=5 is 7.7 feet per second.

Therefore, the correct option is C.

5 0
3 years ago
9. To make lemonade you need 30 ounces of water and
love history [14]

Answer:

A

Step-by-step explanation:

Hopefully this helps

6 0
3 years ago
1/2t + 25; -10 PLEASE HELP
makkiz [27]
You need it to be solved?

4 0
4 years ago
An entrepreneur is considering the purchase of a coin-operated laundry. The current owner claims that over the past 5 years, the
notsponge [240]

Answer:

We conclude that the daily average revenue was actually $675.

Step-by-step explanation:

We are given that the  current owner claims that over the past 5 years, the average daily revenue was $675 with a standard deviation of $75.

A sample of 30 days reveals a daily average revenue of $625.

<u><em>Let </em></u>\mu<u><em> = daily average revenue.</em></u>

So, Null Hypothesis, H_0 : \mu = $675     {means that the daily average revenue was $675}

Alternate Hypothesis, H_A : \mu \neq $675     {means that the daily average revenue was different from $675}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about the population standard deviation;

                       T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample daily average revenue = $625

            \sigma = population standard deviation = $75

            n = sample of days = 30

Since, we are given that we have decided not to reject the null hypothesis which leads us to the conclusion that the daily average revenue was actually $675.

3 0
4 years ago
Betty's bakery bakes white bread and brown bread. The loaves of bread are then stored in a store room that can house only 900 lo
Rainbow [258]
Is this the whole problem?
4 0
3 years ago
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