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A sculptor needs to lift a piece of marble. It is a cuboid with dimensions 1m by 0.6 m by 0.3 m. Marble has a density of 2.7 g/c

geniusboy [140]

P = m/v
To find the mass you have to do Density x Volume.
The volume of the cuboid is 0.18 m cubed and the density is 2.7g/cm cubed.
The 2.7 g/cm cubed must be converted into kg/m cubed to find the mass in kg. Which is 2,700 kg/ m cubed.
2,700 x 0.18 = 486 kg.
The mass of the marble in kg is 486kg

4 0

3 years ago

write the equation of the line in slope intercept form with the given conditions (slope = 3 and passes through (1,-3))

cupoosta [38]

Answer:

Because we have a point and slope, we can use at the beginning the point-slope form: y-y1=m(x-x1)

Step-by-step explanation:

m=3 , x1=1 , y=-3

y-(-3)=3(x-1)

y+3=3x-3 subtract 3 from both sides

y=3x-6 the answer in the slope-intercept form y=mx+b

3 0

4 years ago

The figure is drawn on centimeter grid paper. Find the perimeter of the shaded figure to the nearest tenth.

nevsk [136]

I hope this helps you

8 0

3 years ago

Read 2 more answers

Two buses leave a station at the same time and travel in opposite directions. One bus travels12m/hrslower than the other. If the

Alex Ar [27]

distance = speed * time

the first bus speed = x

second bus = x - 12

the sum of distance = 765 miles

first distance = 6x

second distance = 6 (x -12)

6x + 6(x-12) = 765

x + x -12 = 127.5

2x = 139.5

x = 69.75 mi/h which is the faster bus

the second bus speed = 57.75 mi/h

6 0

2 years ago

Find the Value of Sin A rounded to the nearest hundredth, if necessary.

leonid [27]

Step-by-step explanation:

In trigonometry, the law of sines is an equation that relates the length of the sides of a triangle (any type of triangle) to the sines of its angles. This is expressed mathematically as

$\displaystyle\frac{a}{\sin \alpha} \ = \ \displaystyle\frac{b}{\sin \beta} \ = \ \displaystyle\frac{c}{\sin \gamma}$ ,

where $a$ , $b$ , and $c$ are the lengths of the sides of the triangle and $\alpha$ , $\beta$ , and $\gamma$ are the opposite angles (as shown in the figure below). Likewise, the law is sometimes written as it reciprocals,

$\displaystyle\frac{\sin \alpha}{a} \ = \ \displaystyle\frac{\sin \beta}{b} \ = \ \displaystyle\frac{\sin \gamma}{c}$ .

Therefore,

$\displaystyle\frac{\sin A}{BC} \ = \ \displaystyle\frac{\sin B}{AC} \\ \\ \\ \sin A \ = \ \displaystyle\frac{\sin B \ \times \ BC}{AC} \\ \\ \\\sin A \ = \ \displaystyle\frac{\sin \left(90^{\circ}\right) \ \times \ \sqrt{\left(10\right)^{2} \ - \ \left(\sqrt{78}\right)^{2}}}{10} \\ \\ \\ \sin A \ = \ \dsiplaystyle\frac{\sqrt{22}}{10} \\ \\ \\ \sin A \ = \ 0.47 \ \ \ \ (\text{nearest hundredth})$

Alternatively, you can solve this question using the definition of the trigonometric function sine. For the angle $\theta$ in the figure below,

$\sin \theta \ = \ \displaystyle\frac{\text{opposite}}{\text{hypothenuse}}$ .

Therefore,

$\sin A \ = \ \displaystyle\frac{BC}{AC} \\ \\ \\ \sin A \ = \ \displaystyle\frac{\sqrt{\left(10\right)^{2} \ - \ \left(\sqrt{78}\right)^{2}}}{10} \\ \\ \\ \sin A \ = \ \displaystyle\frac{\sqrt{22}}{10} \\ \\ \\ \sin A \ = \ 0.47 \ \ \ \ (\text{nearest hundredth})$

8 0

3 years ago

PLEASE HELP!!!! I WILL BE REPORTING ANSWERS THAT HAVE NOTHING TO DO WITH THE TOPIC ​

PLEASE HELP!!!! I WILL BE REPORTING ANSWERS THAT HAVE NOTHING TO DO WITH THE TOPIC