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Juli2301 [7.4K]

3 years ago

13

The solution set for 6a2 − a − 5 = 0 is?

2 answers:

Elden [556K]3 years ago

4 0

A = 1, -5/6

you solve the equation for a, by finding a,b,c of the quadratic then applying the quadratic formula

NeX [460]3 years ago

3 0

(a2 + 5) • (a2 + 1) is your answer to this question.

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What number is less than 15.22 Enter your answer as a decimal in the box

Harlamova29_29 [7]

Answer:

15.10 or -15.22

Step-by-step explanation:

3 0

3 years ago

Which polynomial expression are in standard form

postnew [5]

First and third, second can still be simplified.

7 0

3 years ago

What is the volume?<br> 2 mm<br> 8 mm<br> 4 mm<br> cubic millimeters

shutvik [7]

Answer:

64 mm³

Step-by-step explanation:

I am assuming there was a photo to go with this problem

However the general formula to find volume is usually V = l×w×h

It does not matter which measurement is which because they all get multiplied together.
However assigning a name to each unit of measurement we will denoted the length (l) as 2 mm, the width (w) as 8 mm, and the height (h) as 4 mm
Plugging these values into the formula we get: V = (2)(8)(4) = 64 mm³

6 0

3 years ago

Marco's polo team has a budget for new uniforms of $250. If there are 12 members of the team, what can Marco spend on uniforms.

Anit [1.1K]

Your answer is going to be A

7 0

2 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago