The given parallelogram is a rhombus
Solution:
Option A: Rhombus
Let us recall the property of rhombus.
- Diagonals bisect each other at right angles.
- Opposite angles are congruent.
Here diagonals bisect the angles equally each 72°.
Opposite angles are congruent(72° + 72° = 144°).
Hence the given parallelogram is a rhombus.
Option B: Rectangle
Let us recall the property of rectangle.
- Diagonals bisect each other.
- All the angles of a rectangle are 90°.
Here 72° + 72° = 144°, not 90°.
So, the given parallelogram is not a rectangle.
Option C: Square
Let us recall the property of square.
- Diagonals bisect each other.
- All the angles of a square are 90°.
Here 72° + 72° = 144°, not 90°.
So, the given parallelogram is not a square.
Lets solve the quadratic equation:
<span>7x^2 + 2x = 0
(x)(7x + 2) = 0
therefore, for this equation to hold we need, either one of these conditions:
x = 0
or
7x + 2 = 0
from where:
7x = -2
x = -2/7
then, we have two solutions for the equation as expected being quadratic.</span>
Answer:
-23
Step-by-step explanation:
Answer:
x = 4
Step-by-step explanation:
x + 6 +2x = 2x + 6 + 4
combine like terms:
3x + 6 = 2x + 6 + 4
add numbers:
3x + 6 = 2x + 10
subtract 6 on both sides:
3x + 6 - 6 = 2x + 10 - 6
3x = 2x + 4
subtract 2x from both sides:
3x - 2x = 2x - 2x + 4
x = 4
short explanation:
if you look at the equation, both sides have 6 and 2x which would cancel each other out. That would leave x = 4
Answer:
C bro and also my leg hurts