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Citrus2011 [14]
2 years ago
9

An equation with a 9 as a result

Mathematics
1 answer:
Lyrx [107]2 years ago
5 0
3x+3=9
x=2
that way the answer is 9
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(y-7)^2=2y^2-4y+73 solve for y
masya89 [10]

Answer:

y=-4 or y=-6

Step-by-step explanation:

y^2-14y+49=2y^2-4y+73

y^2+10y+24=0

(y+4)(y+6)=0

y=-4 or y=-6

7 0
2 years ago
The following formula relates 3 equantities: force(F),mass(m),and acceleration(a)
weqwewe [10]
We know, Force = mass × acceleration


( i ) :

Given,
Force = 25 units
Mass = 10 units
Acceleration = ?


Solution,

Applying the formula of force,
➡ Force = mass × Acceleration

⏩ 25 = 10 × acceleration

⏩ 25 / 10 =acceleration

⏩ 2.5 units = acceleration




( ii ) :


Given,
Force = 25 units
Acceleration = 5 units
Mass =?



Solution :

Applying formula,
➡ Force = mass × acceleration

⏩ 25 = 5 × mass

⏩ 25 / 5 = mass

⏩ 5 units = mass



\:
5 0
2 years ago
Which of the lines shown above has a negative slope?<br> (1)A<br> (2)B<br> (3)C<br> (4)D<br> (5)E
horrorfan [7]

Answer:

the correct answer is B

Step-by-step explanation:

hope this helps

4 0
2 years ago
Read 2 more answers
(- 40 + 8) x (- 6) – 24
lyudmila [28]

Answer:

168

Step-by-step explanation:

(-40+8)×(-6)-24

=(-32)×(-6)-24

=192-24

=168

7 0
3 years ago
Read 2 more answers
An arithmetic sequence has t1=5 and t2=8 find tn and sn
RoseWind [281]

Answer:

a_n=2+3n

\displaystyle S_n=\frac{7n+3n^2}{2}

Step-by-step explanation:

<u>Arithmetic Sequences </u>

The arithmetic sequences are identified because any term n is obtained by adding or subtracting a fixed number to the previous term. That number is called the common difference.

The equation to calculate the nth term of an arithmetic sequence is:

a_n=a_1+(n-1)r

Where

an = nth term

a1 = first term

r   = common difference

n  = number of the term

The sum of the n terms of an arithmetic sequence is given by:

\displaystyle S_n=\frac{a_1+a_n}{2}\cdot n

We are given the first two terms of the sequence:

a1=5, a2=8. The common difference is:

r = 8 - 5 = 3

Thus the general term of the sequence is:

a_n=5+(n-1)3=5+3n-3=2+3n

\boxed{a_n=2+3n}

The formula for the sum is:

\displaystyle S_n=\frac{5+2+3n}{2}\cdot n

\displaystyle S_n=\frac{7+3n}{2}\cdot n

Operating:

\boxed{\displaystyle S_n=\frac{7n+3n^2}{2}}

4 0
2 years ago
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