Since the standard deviation is not given, we assume the process is a Poisson process, with mean 12000 miles.
From Poisson distribution tables, we see that with a value of lambda(mean)=12000, the lower tail probability for x=12140 miles is 0.9000105, which means that the 90 percentile is 12140 miles.
The lower-tail probability of 9000 miles is 6.2*10^(-181) which is essentially zero.
NOTE: if the problem were modelled with a normal distribution, the probabilities would be completely different.
4/5 = 36/45
1/9= 5/45
then subtract to get 31/45
the simplify
Answer:
Step-by-step explanation:
![2*(3+4x) *2 -5\\6+8x*2-5\\16x =-6-5\\16x = -11\\x = 11/16](https://tex.z-dn.net/?f=2%2A%283%2B4x%29%20%2A2%20-5%5C%5C6%2B8x%2A2-5%5C%5C16x%20%3D-6-5%5C%5C16x%20%3D%20-11%5C%5Cx%20%3D%2011%2F16)
Answer:
c
Step-by-step explanation:
To find the maximum point, differentiate:
D' = -8p +160
Set to zero and solve for p:
D' = 0
⇒ -8p +160 = 0
⇒ 8p = 160
⇒ p = 20
Input p = 20 into the original equation to find D:
D = -4(20)² + 160(20) -310 = 1290
Therefore, the price is $20 and the maximum number of drills is 1,290