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Gnesinka [82]
2 years ago
11

I need help 1 through 13 please and thank you

Mathematics
1 answer:
Andrej [43]2 years ago
7 0

Answer

Let's get to it!

Step-by-step explanation:

1) There are 15 pounds of chees on that platter. (3+5+3+4=15)

2) The total weight is 32 ounces and 6 pounds.

3) 35 gallons of coffee are brewed per day. (5+5+5+5+5+5+5=35)

4) The cook peeled 50 pounds of potatoes per hour (200 divided by 4)

5) There is a total of 4/8 or 1/2 of an ounce

6) 2/8 ounces of oregano is left.

7) This recipe requires 1 and 1/2 pounds of meat.

(This is all I could do without paper) sorry, hope this helps.

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What is 10 times as much as 24.735?
Otrada [13]

Answer: 247.35

Step-by-step explanation:

3 0
3 years ago
Solve x 2 - 4x - 7 = 0 by completing the square. What are the solutions?
Bingel [31]

Answer:

x = 2±sqrt(11)

Step-by-step explanation:

x^2 -4x - 7 =0

Add 7 to each side

x^2 -4x -7+7 =0+7

x^2 -4x =7

To complete the square take the coefficient of the x term and  divide by 2 and then square it.  Add it to both sides

-4 /2 = -2 then square

(-2)^2 = 4

Add 4 to both sides

x^2 -4x+4 =7+4

x^2 -4x+4 = 11

Factor the left side into (x-b/2)^2

(x-2)^2 =11

Take the square root of each side

sqrt((x-2)^2) =±sqrt(11)

x-2 = ±sqrt(11)

Add to to each side

x-2+2 = 2±sqrt(11)

x = 2±sqrt(11)

3 0
4 years ago
Someone please help me? The answe is NOT 4 tried that already
Neko [114]
The answer would be B. 
8 0
3 years ago
Read 2 more answers
The formula for finding the perimeter of a rectangle is P = 2L + 2W. If a rectangle has a perimeter of 68 inches and the length
Artemon [7]

Answer:

Width = 10 inches

Step-by-step explanation:

Given the perimeter of a rectangle of 68 inches, and a length that is 14 inches longer than its width.

We can establish the following values to help us solve for the width of a rectangle:

Perimeter (P) = 68 inches

Length (L) = 14 + W inches

Width (W) = unknown

<h3 /><h3><u>Solve for the Width (W)</u></h3>

P =  2(L + W)  ⇒ This is the same as P = 2L + 2W, except that 2 is factored out from the right-hand side.

Divide both sides by 2:

\displaystyle\mathsf{\frac{P}{2}\:=\:\frac{2(L\:+\:W)}{2}}

\displaystyle\mathsf{\frac{P}{2}\:=L\:+\:W}

Substitute the value of the Perimeter and the length (L) into the formula:

\displaystyle\mathsf{\frac{68}{2}\:=14\:+W\:+\:W}

Combine like terms on the right-hand side, and simplify the left-hand side of the equation:

\displaystyle\mathsf{34\:=14\:+2W}

Subtract 14 from both sides:

34 - 14 = 14 - 14 + 2W

20 = 2W

Divide both sides by 2 to solve for the width (W):

\displaystyle\mathsf{\frac{20}{2}\:=\:\frac{2W}{2}}

W = 10 inches

Therefore, the width of the rectangle is 10 inches.

<h3 /><h3><u>Double-check:</u></h3>

Verify whether the derived value for the width is correct:

P = 2L + 2W

68 = 2(14 + 10) + 2(10)

68 = 2(34) + 20

68 = 48 + 20

68 = 68 (True statement).  

Thus, the length of the rectangle is 34 inches, and the width is 10 inches.

4 0
3 years ago
Solve for x 5 – 57− 2 = 63 please help
umka2103 [35]
5x - 2x = 63 + 57
3x = 120
x = 40
4 0
3 years ago
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