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Sedaia [141]
3 years ago
8

Technical Performance Measures should be selected for those parameters that: [Use Technical Performance Measures to track progre

ss in program risk areas during systems development.]
A. Are expected to have the highest degree of risk.
B. Will not be addressed at technical design reviews.
C. Are expected to exceed the objectives contained in the Capability Development Document (CDD).
D. Will not be subjected to formal test and evaluation.
Business
1 answer:
elixir [45]3 years ago
5 0

Answer:

The correct answer is letter "A": Are expected to have the highest degree of risk.

Explanation:

A Technical Performance Measure or TPM is an instrument that shows how well a program meets its specifications or goals. Technical Performance Measures are useful for risk tracking to identify the factors of an objective that can potentially affect the original plan of an organization.

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International organizations prefer to rely on Blank______ for measuring the value produced in an economy.
Ilia_Sergeevich [38]

Answer:

I thinks it's gross national income

Explanation:

I am guessing

3 0
2 years ago
College students often buy cheap pizza because it’s more affordable. Suppose after graduating, college students find high paying
Margarita [4]

Answer:

D) The demand for cheap pizza will decrease because demand for cheap pizza is negative related to income.

As students finds high paying job, they are now able to buy more expensive pizza, which means that a number of customers for cheap pizza will be decreased

5 0
3 years ago
Assume that on December 31, 2019, Kimberly-Clark Corp. signs a 10-year, non-cancelable lease agreement to lease a storage buildi
Anika [276]

Answer:

a) the journal entry to record the signing of the lease agreement:

December 31, 2019, lease agreement signed

Dr Right of use 483,360

   Cr Lease liability 483,360

the lease liability must record the present value of the 10 annual lease payments: $68,099 and 8% discount rate:

present value of an annuity due = payment + {payment x [1 - (1 + r)⁻⁽ⁿ⁻¹⁾]/r}

  • payment = 66,699
  • r = 8%
  • n - 1 = 10 - 1 = 9

PV annuity due = 66,699 + {66,699 x [1 - (1 + 0.08)⁻⁹]/0.08} = 66,699 + 416,661 = $483,360

the journal entries to record the annual lease payments:

December 31, 2019, first annual lease payment

Dr Lease liability 66,699

   Cr Cash 66,699

December 31, 2020, second annual lease payment

Dr Lease liability 33,366

Dr Interest expense 33,333

   Cr Cash 66,699

interest expense = $416,661 x 8% = $33,333

December 31, 2020, depreciation expense

Dr Depreciation expense - leased building 48,336

   Cr Accumulated depreciation - leased building 48,336

December 31, 2021, third annual lease payment

Dr Lease liability 36,035

Dr Interest expense 30,664

   Cr Cash 66,699

interest expense = $383,295 x 8% = $30,664

December 31, 2021, depreciation expense

 Dr Depreciation expense - leased building 48,336

   Cr Accumulated depreciation - leased building 48,336

b) this would increase the right to use asset and lease liability by:

= -$5,000 + $1,000 = $4,000

c) this would increase the right to use asset and lease liability by:

= 5,000 + {5,000 x [1 - (1 + 0.08)⁻⁹]/0.08} = $36,234

8 0
3 years ago
The following information is from the materials requisitions and time tickets for Job 9-1005 completed by Great Bay Boats. The r
Nata [24]

Answer:

Total cost for Job 9-1005 = $ 5,085

Explanation:

Calculation for total cost for Job 9-1005

Direct materials

Q-4698          $1,250

Q-4725          <u>$1,000</u>

<u>Total Direct material cost = $ 2,250</u>

Direct labor

W-3393          $ 600

W-3479          $ 450

W-3559          <u>$ 300</u>

<u>Total direct labour Cost = $ 1,350</u>

add: Overhead cost 110% of total direct labor cost: $1,350×110%= $1,485

Total Cost on Job is: $2,250+$1,350+$1,485 = $5,085

5 0
3 years ago
(Growth) The U.S. Census estimated that the world population was 6 bil- lion in 1999, and it was increasing 212,000 per day. Wha
lianna [129]

Answer:

Annual growth rate = 1.29% per year

Population in 2050 = 11.53 billion

Explanation:

Data provided in the question:

Population in 1999 = 6 billion = 6,000,000,000

Rate of increase in population = 212,000 per day

Now,

Number of days in a year = 365

Therefore,

Annual growth rate

= [ Growth rate per day × Number of days in a year ] ÷ initial population

= [ 212,000 × 365 ] ÷ 6,000,000,000

= 0.0129 per year

or

= 0.0129 × 100%

= 1.29% per year

Now,

2050 is 51 year from 1999

Population in 2050 = Population in 1999 × ( 1 + rate )ⁿ

= 6,000,000,000 × ( 1 + 0.0129 )⁵¹

= 11.53 billion

7 0
3 years ago
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