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3 years ago

Complete the equation of the line through (-8-2) and (-4-6)

Mathematics

1 answer:

Kisachek [45]3 years ago

4 0

Answer:

Step-by-step explanation:

since you are given two points use the point- slope formula and the slope formula

y-y1 = m( x -x1) and m = y2 -y1 / x2 - x1

find the slope m, 1st

p1 = (x1,y1) given (-8,-2)

p2 = (x2,y2) given (-4,-6)

m = -6-(-2) / -4-(-8)

m = -6+2 / -4+8

m = -4 / 4

m = -1 :)

now use the slope you just found and the point-slope with either given point.. pick one.. which ever seems easier... they seem about the same to me

y - (-8) = -1(x-(-2))

y+8 = -1(x+2)

y+8 = -x-2

y = -x-2-8

y= -x-10

and your done :)

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3 years ago

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Answer:

The real and imaginary parts of the result are $\frac{1441}{1601}$ and $\frac{4}{1601}$ , respectively.

Step-by-step explanation:

Let be $f(z) = \frac{z}{z+1}$ , the following expression is expanded by algebraic means:

$f(z) = \frac{z\cdot (z-1)}{(z+1)\cdot (z-1)}$

$f(z) = \frac{z^{2}-z}{z^{2}-1}$

$f(z) = \frac{z^{2}}{z^{2}-1}-\frac{z}{z^{2}-1}$

If $z = 4 - i5$ , then:

$z^{2} = (4-i5)\cdot (4-i5)$

$z^{2} = 16-i20-i20-(-1)\cdot (25)$

$z^{2} = 41 - i40$

Then, the variable is substituted in the equation and simplified:

$f(z) = \frac{41-i40}{41-i39} -\frac{4-i5}{41-i39}$

$f(z) = \frac{37-i35}{41-i39}$

$f(z) = \frac{(37-i35)\cdot (41+i39)}{(41-i39)\cdot (41+i39)}$

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$f(z) = \frac{2882+i8}{3202}$

$f(z) = \frac{1441}{1601} + i\frac{4}{1601}$

The real and imaginary parts of the result are $\frac{1441}{1601}$ and $\frac{4}{1601}$ , respectively.

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Answer:

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