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BabaBlast [244]
3 years ago
13

City x has a population of 3x10 to the fifth power. City y has a population of 6x10 to the sixth power. Which statement is true?

Mathematics
1 answer:
belka [17]3 years ago
3 0

Answer:

B. 20x larger

Step-by-step explanation:

3x10^5 = 300000

6x10^6 = 6000000

6000000/300000 = 20

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<span>(A) Find the approximate length of the plank. Round to the nearest tenth of a foot.
Given that the distance of the ground is 3ft.
In order to get the length of the plank,
we can use the this one.

cos 49 = ground / plank
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plank = cos 49 / 3
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</span><span>(b) Find the height above the ground where the plank touches the wall. Round to the nearest tenth of a foot.
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The remaining angle is equal to
angle = 180 - (90+49)
angle = 41

Finding the height.
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A land owner is planning to build a fenced-in, rectangular patio behind his garage, using his garage as one of the "walls." He
Vitek1552 [10]

Answer:

Maximum area = 800 square feet.

Step-by-step explanation:

In the figure attached,

Rectangle is showing width = x ft and the side towards garage is not to be fenced.

Length of the fence has been given as 80 ft.

Therefore, length of the fence = Sum of all three sides of the rectangle to be fenced

80 = x + x + y

80 = 2x + y

y = (80 - 2x)

Now area of the rectangle A = xy

Or function that represents the area of the rectangle is,

A(x) = x(80 - 2x)

A(x) = 80x - 2x²

To find the maximum area we will take the derivative of the function with respect to x and equate it to zero.

A'(x)=\frac{d}{dx}(80x-2x^{2})

             = 80 - 4x

A'(x) = 80 - 4x = 0

4x = 80

x = \frac{80}{4}

x = 20

Therefore, for x = 20 ft area of the rectangular patio will be maximum.

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