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drek231 [11]
3 years ago
10

Write 2/3 as a decimal rounded to 3 sighificant figures

Mathematics
1 answer:
jasenka [17]3 years ago
8 0

Answer:

0.667

Step-by-step explanation:

2/3= 0.66666

Dividing the given value to obtain the decimal value gives:

\frac{2}{3} =0.6666666666666667

The last number is 7 which is greater than 5 this will increment the previous number by 1.

As,the previous values are also '6', so this step will continue till three significant figures.

   0.666666666666667\\0.66666666666667\\0.6666666666667\\0.666666666667\\0.66666666667\\0.6666666667\\0.666666667\\0.66666667\\0.6666667\\0.666667\\0.66667\\0.6667\\0.667

             

So the value rounded up to 3 significant is 0.667

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VashaNatasha [74]

Answer:

29

Step-by-step explanation:

As it is a list of prime number, the sequence continues with 29 being the next prime number after 23.

6 0
3 years ago
i walked 3y - 2c + 600 meters yesterday. today, i walked 10,000 meters. how many more miles did i walk today?
Leokris [45]
To find out how much more you walked today, you want to find the difference between the two days, which is 10,000-(<span>3y - 2c + 600) = 9400-3y+2c using the distributive property (the negative sign in front of the parenthesis is essentially a -1)</span>
8 0
3 years ago
How many numbers are 10 units from 0 on the number line?​
Travka [436]

Answer:

2 Numbers; -10, and 10.

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Someone please help me with this question I need the answer plsss
kow [346]

Answer:

6

Step-by-step explanation:

The slope is: \frac{y_{2} -y_{1} }{x_{2} -x_{1} }. In this case, for the numerator you get 30. For the denominator you get 5. Divide 30/5 to get 6 as your final slope.

Hope it helps!

5 0
3 years ago
Read 2 more answers
Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.
lubasha [3.4K]

Answer:

The answer is option C.

<h3>-6, -5 2/5, -4 1/5</h3>

Step-by-step explanation:

The arithmetic sequence is given by

A(n) =  - 6 + (n - 1)( \frac{1}{5} )

where n is the number of terms

<u>For</u><u> </u><u>the</u><u> first</u><u> </u><u>term</u>

n = 1

So we have

A(1) =  - 6 + (1 - 1)( \frac{1}{5} )

=  - 6 + (0)( \frac{1}{5} )

=  - 6

<u>For</u><u> </u><u>the</u><u> </u><u>fou</u><u>rth</u><u> term</u>

n = 4

A(4) =  - 6 + (4 - 1)( \frac{1}{5} )

=  - 6 + (3)( \frac{1}{5} )

=  - 5 \frac{2}{5}

<u>For</u><u> </u><u>the</u><u> </u><u>tenth</u><u> </u><u>term</u>

n = 10

A(10) =  - 6 + (10 - 1)( \frac{1}{5} )

=  - 6 + (9)( \frac{1}{5} )

=  - 4 \frac{1}{5}

Hope this helps you

4 0
3 years ago
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