Find the x-intercept of the equation 4x-y=5

Schach [20]

The data given on the table about the ten participants in the health study shows that B. The post-run mean and median are the same value.

This can be found as:

= (87 + 95 + 96 + 101 + 110 + 104 + 100 + 101 + 90 + 96) / 10

= 98

<h3>What is the post run median?</h3>

First order the pulses from smallest to largest:

= 87, 90, 95, 96, 96, 100, 101, 101, 104, 110

The two digits in the middle are:

96 and 100

The median will be:

= (96 + 100) / 10

= 98

In conclusion, option B is correct.

Find out more on the median at brainly.com/question/396397.

8 0

2 years ago

Answer using elimination will mark brainist<br> -4x+3y=-5<br> 4x-5y=3<br><br> 2x+3y=36<br> 10x-6y=12

Oksanka [162]

Answer:

Step-by-step explanation:

For Case -1

$\Rightarrow -4x+3y=-5\quad \ldots(i)$

$\Rightarrow 4x-5y=3$

$\Rightarrow 4x=5y+3$

Put the value of $4x$ in equation $(i)$ we get

$\Rightarrow -(5y+3)+3y=-5$

$\Rightarrow -5y+3y-3=-5$

$\Rightarrow 2=2y$

$\Rightarrow y=1$

and thus $4x=5(1)+3$

$x=\frac{8}{4}=2$

Case-2

$10x-6y=12\quad \ldots(i)$

$2x+3y=12\quad \ldots(ii)$

Now multiply $(ii) by 5 and subtract it from (i)$

$10x-6y=12$

$10x+15y=+180$

$\cdots \cdots \cdots$

$-21y=-168$

$y=8$

and $=6$

8 0

3 years ago

An investment of $8,000 earns interest at an annual rate of 7% compounded continuously. Complete parts (A) and (B) below. Click

Sergeeva-Olga [200]

Answer:

A. $\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

B. $\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

Step-by-step explanation:

Given that:

An investment of Amount = $8000

earns at an annual rate of interest = 7% = 0.07 compounded continuously

The objective is to :

A) Find the instantaneous rate of change of the amount in the account after 2 year(s).

we all know that:

$A = Pe^{rt}$

where;

$A = (8000) \ e ^{0.7t}$

The instantaneous rate of change = $\dfrac{dA}{dt}$

$\dfrac{dA}{dt} = \dfrac{d}{dt}(8000 \ e ^{0.07t} )$

$= 8000 \dfrac{d}{dt}e^{0.07 \ t}$

$\dfrac{dA}{dt}= 8000 (0.07)e^{0.07 \ t}$

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 2 years; the instantaneous rate of change is:

$\dfrac{dA}{dt}|_{t=2}= 560 e^{0.07 \times 2}$

$\mathtt{\dfrac{dA}{dt}|_{t=2}=644.15}$

(B) Find the instantaneous rate of change of the amount in the account at the time the amount is equal to $12,000.

Here the amount = 12000

$12000 = (8000)e^{0.07 \ t}$

$\dfrac{12000 }{8000}= e^{0.07 \ t}$

$1.5= e^{0.07 \ t}$

㏑(1.5) = 0.07 t

0.405465 = 0.07 t

t = 0.405465 /0.07

t = 5.79

$\dfrac{dA}{dt}= 560 e^{0.07 \ t}$

At t = 5.79

$\dfrac{dA}{dt}|_{t = 5.79}= 560 e^{0.07 \times 5.79}$

$\mathtt{\dfrac{dA}{dt}|_{t = 5.79}= 839.86 }$

7 0

3 years ago

The terminal tower in cleveland ohio is 239 ft shorter than key tower also in cleveland the total heights of the two buildings i

Nutka1998 [239]

T + k = 1655
k = t + 239

now we sub
t + t + 239 = 1655
2t + 239 = 1655
2t = 1655 - 239
2t = 1416
t = 1416/2
t = 708 ft <== terminal tower

k = t + 239
k = 708 + 239
k = 947 ft <=== key tower

8 0

4 years ago

9/11 - 1/2 in it's simplest form

Murrr4er [49]

Answer:

7/22

Step-by-step explanation:

Step 1: <u>Define/explain.</u>

To subtract fractions with different denominators, you must first find the least common denominator (LCM).

You can do this by listing the multiples of each denominator.

Step 2: <u>Solve.</u>

11: 11, 22, 33, 44, 55, 66, 77, 88, 99, 110

2: 2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22

22 is the LCM.

Now, we change the fractions to where they both have denominators of 22.

**REMEMBER: WHICHEVER NUMBER YOU MULTIPLY THE DENOMINATOR BY, YOU MULTIPLY IT BY THE NUMERATOR AS WELL!!**

$9/11*2/2=18/22$

$1/2*11/11=11/22$

Now, subtract as normal.

$18/22-11/22=7/22$

$7/22 (simplified).$

Step 3: <u>Conclude.</u>

Therefore, 9/11 - 1/2 = 7/22.

5 0

3 years ago