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3 years ago

You are given the great circle of a sphere is a length of 60 miles. What is the volume of the sphere?

Mathematics

1 answer:

Mazyrski [523]3 years ago

4 0

Answer:

V = 3646.5 miles^3

Step-by-step explanation:

The circumference formula applies here. C = 2pi*r, and so r = C / [2pi].

Thus, r = 60 miles / 6.28 = 9.55 miles.

The volume formula is next. V = (4/3)pi*r^3.

With r = 9.55 miles, this comes to V = (4/3)(3.14)(9.55)^3 miles^3, or

V = 3646.5 miles^3

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abrl,belle and cindy have $408 altogeter.belle has $7 more than cindy and $5 more than abel.how much does abel have?

faltersainse [42]

ABC = 408
C + 7 = B
A + 5 = B

B - 7 + B - 5 + B = 408
3B - 12 = 408
+ 12 = +12
3B = 420
/3 = /3
B = 120
A = 115
C = 113
The answer is A = 115, Abel has $ 115

4 0

2 years ago

An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand

Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

b) We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error for the mean would be:

$\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14$

Part b

We want this probability:

$P(\bar X >120)$

And we can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And replacing we got:

$z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143$

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

$P( z>2.143) = 1-P(Z$

4 0

3 years ago

Julie is a cashier. She can ring up 12 customers in 9 mintesutes. At the rate, how many minutes does it take for her to ring up

oksano4ka [1.4K]

Answer:

5.2

Step-by-step explanation:

ok so we need to find the unit rate( how many customers per minute) and thats 12 divided by 9 which is 1.3 minutes per customer so now we need to find what 1.3 minutes is x4 customers. This brings us to 5.2.

6 0

2 years ago

Figure one and figure 2 are similar quadrilaterals. Which proportion must be true?

amm1812

Step-by-step explanation:

option C is the correct answer of this question

5 0

3 years ago

HELPppp im confused .

mars1129 [50]

Answer:

2x + 7 + 3 - 2

Step-by-step explanation:

standard form

8 0

3 years ago