Question

Write a third degree polynomial function that has real zeros -1, -2 and 4

Answer 1

Answer:

f(x) = $x^{3} - x^{2} - 10x -8$

Step-by-step explanation:

All you have to do is multiply (x + 1)(x + 2)(x - 4)

You should get $x^{3} - x^{2} - 10x -8$

So,  f(x) = $x^{3} - x^{2} - 10x -8$