Answer:
Step-by-step explanation:
C=9P
P=2(L+W)
C=18(L+W)
C=18(8(12)+7(12))
C=18(96+84)
C=18(180)
C=$3240
So you do not have enough money to enclose the property.
First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)
If the base and height were each 3, then the hypotenuse would need to be:
3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24
This is larger than sqrt(3), so this cannot be a right triangle.
If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46
This is larger than 3, this cannot be a right triangle.
The answer is b) no.
Answer:
D
Step-by-step explanation:
f(x) < 25
x² - 11 < 25
x² < 36
-6 < x < 6
Answer:
C.
Step-by-step explanation:
I can explain in comments if needed, but c is the correct answer :)
Answer:
Explanation:
Number the sides of the decagon: 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10, from top (currently red) clockwise.
- The side number one can be colored of five different colors (red, orange, blue, green, or yellow): 5
- The side number two can be colored with four different colors: 4
- The side number three can be colored with three different colors: 3
- The side number four can be colored with two different colors: 2
- The side number five can be colored with the only color left: 1
- Each of the sides six through ten can be colored with one color, the same as its opposite side: 1
Thus, by the multiplication or fundamental principle of counting, the number of different ways to color the decagon will be:
- 5 × 4 × 3 × 2 ×1 × 1 × 1 × 1 × 1 × 1 = 120.
Notice that numbering the sides starting from other than the top side is a rotation of the decagon, which would lead to identical coloring decagons, not adding a new way to the number of ways to color the sides of the figure.
