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3 years ago

Y=(x+3)(x-4)(x+1)^2 sulutions? Multiplicity?

Mathematics

1 answer:

Eddi Din [679]3 years ago

7 0

Answer:

Y = (x + 3)(x - 4)(x + 1)^2

Y = (x^2 - x - 12)(x^2 + 2x + 1)

Y = x^4 + 2x^3 + x^2 - x^3 - 2x^2 - x - 12x^2 - 24x - 12

Y = x^4 + x^3 - 13x^2 - 25x - 12

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3 years ago

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Step-by-step explanation:

The absolute value function always gives a positive value, however, the expression inside can be positive or negative, that is

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As a check

Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.

| - 3(- $\frac{2}{3}$ ) + 16 | = | 2 + 16 | = | 18 | = 18 ← True

| - 3( $\frac{34}{3}$ ) + 16 | = | - 34 + 16 | = | - 18 | = 18 ← True

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8 0

3 years ago

Read 2 more answers