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Sergio [31]
3 years ago
12

Y=(x+3)(x-4)(x+1)^2 sulutions? Multiplicity?

Mathematics
1 answer:
Eddi Din [679]3 years ago
7 0

Answer:

Y = (x + 3)(x - 4)(x + 1)^2

Y = (x^2 - x - 12)(x^2 + 2x + 1)

Y = x^4 + 2x^3 + x^2 - x^3 - 2x^2 - x - 12x^2 - 24x - 12

Y = x^4 + x^3 - 13x^2 - 25x - 12

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Math 2 Of high school
Daniel [21]

Answer:

  • B. BC = 18 so ∆ABC ~ ∆DEF by SAS

Step-by-step explanation:

\bf \cfrac{AB}{DE}  =  \cfrac{BC}{EF}

  • \bf \cfrac{15}{10}  =  \cfrac{BC}{12}
  • \bf  \cfrac{3}{2}  =  \cfrac{BC}{12}
  • \bf BC =  \cfrac{3}{2}  \times 12
  • \bf 3 \times 6
  • \bf BC = 18
  • \bf \angle B = \angle \: E

So, ∆ABC ~ ∆DEF by SAS.

<h3><u>------------------------------------</u></h3>
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2 years ago
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Answer:

In this question, we can use the Pythagorean theorem to solve for x.

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x^2 = 24^2 -11^2

x is about 21.3

Let me know if this helps!

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3 years ago
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Answer:

Step-by-step explanation:

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On a phone here and no access to paper but you must first find the midpoint of AC which is the average of the coordinates. The perpendicular bisector will have a gradient that multiplies by AC's gradient to make -1. This will obviously pass through its mid point so as long as you know how to use y=mx+c you should be good.
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den301095 [7]

Answer: The third option.

Step-by-step explanation:

This is an equation because it has an equals sign that can be solved for, making it an equation.

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3 years ago
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