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2 years ago

Half of a number is 16. Write an equation and solve to find the number?

Mathematics

2 answers:

Kobotan [32]2 years ago

7 0

Answer:

16 / 2, 8

Step-by-step explanation:

Half always means divide by two. 16 divided by 2 is 8. That last sentence is also the equation.

inna [77]2 years ago

3 0

A number divide by 2 equals 16.
n/2 = 16
Do the inverse to find the number. Opposite of division is multiplication.
16 x 2 = 32

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What is 3.7 reapeting as a mixed number?

Masteriza [31]

Answer:

$3 \frac{7}{9}$

Step-by-step explanation:

We know that the first digit of 3.7, 3, will just be a 3.

However, if we have $.\overline{77}$ , we have to know what gets this.

If we have a number over 9, it will be that number repeating (excluding 9 itself).

So if we have .77 repeating, it would have to be $\frac{7}{9}$ , adding 3 to this gets us $3 \frac{7}{9}$ .

Hope this helped!

3 0

2 years ago

2(a + 3) = −4 i need help i don't understand

kkurt [141]

Answer: a = -5

Step-by-step explanation:

2(a+3)=-4

Distribute

2a+6=-4

subtract the six with the four and you get -10

-6-4=-10

now divide 2a with -10

you get a= -5

you can plug the answer in

3 0

2 years ago

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Suppose f(x)=x^2.Find the graph of f(x+3)

Mkey [24]

Replace x with x+3:
f(x+3) = (x+3)²
which is x² translated 3 units left

5 0

2 years ago

Read 2 more answers

Need help with question 3. ASAP PLS. Much appreciated :)

s2008m [1.1K]

Emma is running faster than Maggie. The point on the graph where the two lines intersect represents the spot on the running track where Maggie and Emma are at the same distance from the starting point.
Since Emma starts ahead of Maggie, Maggie has to run FASTER to catch up with Emma.
I hope this helps :)

4 0

2 years ago

Find the area of a triangle bounded by the y-axis, the line f(x)=9−4/7x, and the line perpendicular to f(x) that passes through

Setler79 [48]

<u>ANSWER: </u>

The area of the triangle bounded by the y-axis is $\frac{7938}{4225} \sqrt{65} \text { unit }^{2}$

<u>SOLUTION:</u>

Given, $f(x)=9-\frac{-4}{7} x$

Consider f(x) = y. Hence we get

$f(x)=9-\frac{-4}{7} x$ --- eqn 1

$y=9-\frac{4}{7} x$

On rewriting the terms we get

4x + 7y – 63 = 0

As the triangle is bounded by two perpendicular lines, it is an right angle triangle with y-axis as hypotenuse.

Area of right angle triangle = $\frac{1}{ab}$ where a, b are lengths of sides other than hypotenuse.

So, we need find length of f(x) and its perpendicular line.

First let us find perpendicular line equation.

Slope of f(x) = $\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-4}{7}$

So, slope of perpendicular line = $\frac{-1}{\text {slope of } f(x)}=\frac{7}{4}$

Perpendicular line is passing through origin(0,0).So by using point slope formula,

$y-y_{1}=m\left(x-x_{1}\right)$

Where m is the slope and $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)$

$y-0=\frac{7}{4}(x-0)$

$y=\frac{7}{4} x$ --- eqn 2

4y = 7x

7x – 4y = 0

now, let us find the vertices of triangle, one of them is origin, second one is point of intersection of y-axis and f(x)

for points on y-axis x will be zero, to get y value, put x =0 int f(x)

0 + 7y – 63 = 0

7y = 63

y = 9

Hence, the point of intersection is (0, 9)

Third vertex is point of intersection of f(x) and its perpendicular line.

So, solve (1) and (2)

$\begin{array}{l}{9-\frac{4}{7} x=\frac{7}{4} x} \\\\ {9 \times 4-\frac{4 \times 4}{7} x=7 x} \\\\ {36 \times 7-16 x=7 \times 7 x} \\\\ {252-16 x=49 x} \\\\ {49 x+16 x=252} \\\\ {65 x=252} \\\\ {x=\frac{252}{65}}\end{array}$

Put x value in (2)

$\begin{array}{l}{y=\frac{7}{4} \times \frac{252}{65}} \\\\ {y=\frac{441}{65}}\end{array}$

So, the point of intersection is $\left(\frac{252}{65}, \frac{441}{65}\right)$

Length of f(x) is distance between $\left(\frac{252}{65}, \frac{441}{65}\right)$ and (0,9)

$\begin{aligned} \text { Length } &=\sqrt{\left(0-\frac{252}{65}\right)^{2}+\left(9-\frac{441}{65}\right)^{2}} \\ &=\sqrt{\left(\frac{252}{65}\right)^{2}+0} \\ &=\frac{252}{65} \end{aligned}$

Now, length of perpendicular of f(x) is distance between $\left(\frac{252}{65}, \frac{441}{65}\right) \text { and }(0,0)$

$\begin{aligned} \text { Length } &=\sqrt{\left(0-\frac{252}{65}\right)^{2}+\left(0-\frac{441}{65}\right)^{2}} \\ &=\sqrt{\left(\frac{252}{65}\right)^{2}+\left(\frac{441}{65}\right)^{2}} \\ &=\frac{\sqrt{(12 \times 21)^{2}+(21 \times 21)^{2}}}{65} \\ &=\frac{63}{65} \sqrt{65} \end{aligned}$

Now, area of right angle triangle = $\frac{1}{2} \times \frac{252}{65} \times \frac{63}{65} \sqrt{65}$

$=\frac{7938}{4225} \sqrt{65} \text { unit }^{2}$

Hence, the area of the triangle is $\frac{7938}{4225} \sqrt{65} \text { unit }^{2}$

8 0

2 years ago